Problem 34
Question
Find \(f+g, f-g,\) fg, and \(\frac{f}{x}\). Determine the $d o^{2}$$$ f(x)-x-6, g(x)-5 x^{2} $$
Step-by-Step Solution
Verified Answer
\(f(x) + g(x) = 5x^{2} + x - 6\), \(f(x) - g(x) = -5x^{2} + x - 6\), \(f(x) \cdot g(x) = 5x^{2}(x - 6)\), \(\frac{f(x)}{x} = 1 - \frac{6}{x}\)
1Step 1: f+g
To perform the operation \(f + g\), simply add the functions \(f(x)\) and \(g(x)\) together:\(f(x) + g(x) = (x - 6) + 5x^{2}\)
2Step 2: f-g
For \(f - g\), subtract \(g(x)\) from \(f(x)\):\(f(x) - g(x) = (x - 6) - 5x^{2}\)
3Step 3: fg
For the multiplication \(fg\), multiply \(f(x)\) by \(g(x)\):\(f(x) \cdot g(x) = (x - 6) \cdot 5x^{2}\)
4Step 4: \(\frac{f}{x}\)
To divide \(f\) by \(x\), divide \(f(x)\) by \(x\):\(\frac{f(x)}{x} = \frac{(x - 6)}{x}\)
Key Concepts
Function AdditionFunction SubtractionFunction MultiplicationFunction Division
Function Addition
Function addition involves combining two functions by adding their corresponding outputs for any given input. This operation is pretty straightforward and can be done with any two functions, whether they're linear, quadratic, or of another type. For example, given two functions, \( f(x) = x - 6 \) and \( g(x) = 5x^2 \), you simply add the expressions:
- \( f(x) + g(x) = (x - 6) + 5x^2 \).
Function Subtraction
Subtracting functions is a similar process to adding them, but instead, you take one function's output away from the other. Just as with addition, you realign the functions' terms before executing the operation. Using the example functions again, \( f(x) = x - 6 \) and \( g(x) = 5x^2 \), subtraction is as follows:
- \( f(x) - g(x) = (x - 6) - 5x^2 \).
Function Multiplication
Function multiplication involves multiplying the outputs of two functions for a given input. This operation combines the terms of each function for a more complex product. Consider \( f(x) = x - 6 \) and \( g(x) = 5x^2 \). To find their product:
- \( f(x) \cdot g(x) = (x - 6) \cdot 5x^2 \).
Function Division
Function division splits the output of one function by another. However, division comes with additional complexities, particularly since dividing by a variable can lead to undefined values. Let's divide \( f(x) = x - 6 \) by \( x \):
- \( \frac{f(x)}{x} = \frac{(x - 6)}{x} \).
Other exercises in this chapter
Problem 34
Write the standard form of the equation of the circle with the given center and radius. $$\text { Center }(2,-1), r=4$$
View solution Problem 34
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Passing through \((-2,-5)\) and \((6,-5)\)
View solution Problem 35
What is a secant line?
View solution Problem 35
Write the standard form of the equation of the circle with the given center and radius. $$\text { Center }(-1,4), r=2$$
View solution