Problem 34
Question
Find each of the given projections if \(\mathbf{u}=3 \mathbf{i}+2 \mathbf{j}+\mathbf{k}, \mathbf{v}=2 \mathbf{i}-\mathbf{k}\), and \(\mathbf{w}=\mathbf{i}+5 \mathbf{j}-3 \mathbf{k}\). \(\operatorname{proj}_{\mathbf{i}} \mathbf{u}\)
Step-by-Step Solution
Verified Answer
\(\operatorname{proj}_{\mathbf{i}} \mathbf{u} = 3 \mathbf{i}\)
1Step 1: Find Dot Product of u and i
First, identify the unit vector \(\mathbf{i}\), which is \((1, 0, 0)\). Calculate the dot product of \(\mathbf{u}\) and \(\mathbf{i}\) using the formula \(\mathbf{u} \cdot \mathbf{i} = 3 \times 1 + 2 \times 0 + 1 \times 0 = 3\).
2Step 2: Calculate Magnitude of i
The magnitude of the unit vector \(\mathbf{i}\) is 1, as it is a unit vector. Thus, \(\|\mathbf{i}\| = 1\).
3Step 3: Compute Projection Formula
The formula for the projection of \(\mathbf{u}\) onto \(\mathbf{i}\) is given by \(\operatorname{proj}_{\mathbf{i}} \mathbf{u} = \frac{\mathbf{u} \cdot \mathbf{i}}{\|\mathbf{i}\|^2} \mathbf{i}\). Since the magnitude of \(\mathbf{i}\) is 1, \(\|\mathbf{i}\|^2 = 1\).
4Step 4: Calculate the Projection
Substitute the values into the projection formula: \(\operatorname{proj}_{\mathbf{i}} \mathbf{u} = \frac{3}{1} \cdot \mathbf{i} = 3 \mathbf{i}\).
Key Concepts
Dot ProductUnit VectorMagnitudeProjection Formula
Dot Product
The dot product is a fundamental concept in vector mathematics. It is essentially a way to multiply two vectors to get a scalar (a single number) result. To calculate the dot product of vectors \(\mathbf{u}\) and \(\mathbf{v}\), you follow this formula:
- Multiply each corresponding component of the vectors.
- Add those products together.
Unit Vector
A unit vector is a vector that has a magnitude of one. It is used to specify directions without concerning the scale.
- Mathematically, a unit vector in a given direction can be computed by dividing any non-zero vector by its magnitude.
- Common unit vectors in the Cartesian coordinate system include \(\mathbf{i}\), \(\mathbf{j}\), and \(\mathbf{k}\), representing directions along the x, y, and z axes, respectively.
Magnitude
The magnitude of a vector quantifies its length or size. Think of it like the vector's total displacement from the origin when plotted in space.To find the magnitude of a vector \(\mathbf{a} = (a_1, a_2, a_3)\), use the formula:\[ \|\mathbf{a}\| = \sqrt{a_1^2 + a_2^2 + a_3^2} \]
- This formula is derived from the Pythagorean theorem, extended into three dimensions for a 3D space.
- With unit vectors like \(\mathbf{i}, \mathbf{j}, \mathbf{k}\), their magnitude is always 1, simplifying many calculations.
Projection Formula
The projection formula allows us to "project" one vector onto another, essentially finding a component of the vector in the direction of the other.The formula for projecting \(\mathbf{u}\) onto \(\mathbf{v}\) (where \(\mathbf{v}\) is the vector we project onto) is:\[\operatorname{proj}_{\mathbf{v}} \mathbf{u} = \frac{\mathbf{u} \cdot \mathbf{v}}{\|\mathbf{v}\|^2} \mathbf{v}\]Here's a breakdown:
- The dot product \(\mathbf{u} \cdot \mathbf{v}\) measures the extent to which \(\mathbf{u}\) is in the direction of \(\mathbf{v}\).
- \(\|\mathbf{v}\|^2\) in the denominator scales the projection appropriately, involving the length of \(\mathbf{v}\).
- Multiplying by \(\mathbf{v}\) ensures the resulting vector is in the direction of \(\mathbf{v}\).
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