Problem 34
Question
Fill in the missing step(s). $$\begin{aligned} \frac{\tan x-\cot x}{\tan x+\cot x} &=\frac{\frac{\sin x}{\cos x}-\frac{\cos x}{\sin x}}{\frac{\sin x}{\cos x}+\frac{\cos x}{\sin x}} \\ &= \text { _____} \\ &=\frac{\sin ^{2} x-\cos ^{2} x}{1} \\ &=\sin ^{2} x-\cos ^{2} x \\ &= \text { _____} \\ &=1-2 \cos ^{2} x \end{aligned}$$
Step-by-Step Solution
Verified Answer
The missing steps are \(\frac{\sin^2x - \cos^2x}{\sin x \cos x + \cos x \sin x}\) and \( 2\cos^2x - 1 = -2\cos^2 x + 1 \)
1Step 1: Substitute the given values
Replace the given trigonometric terms \(\tan{x}\) and \(\cot{x}\) with \(\frac{\sin x}{\cos x}\) and \(\frac{\cos x}{\sin x}\) respectively. The equation gets transformed to \(\frac{\frac{\sin x}{\cos x}-\frac{\cos x}{\sin x}}{\frac{\sin x}{\cos x}+\frac{\cos x}{\sin x}}\)
2Step 2: Find common denominators in numerator and denominator
Express the given expression with common denominators. This results in \(\frac{\sin^2x - \cos^2x}{\sin x \cos x + \cos x \sin x}\). This step fills the first gap
3Step 3: Simplification
On simplification, the denominator turns out to be \(\sin x \cos x + \cos x \sin x\) is equivalent to \(1\), hence the expression becomes \(\sin^2 x - \cos^2 x\)
4Step 4: Using a trigonometric identity
By using the identity \(\sin^2 x = 1 - \cos^2 x\), the expression becomes \(2\cos^2 x - 1\) which is simplified as \(-2\cos^2 x + 1\). This fills the second gap
5Step 5: Final simplification
Noting that the expression we got in step 4 is just a reversal of the expression we want, the expression thus changes to \(1 - 2\cos^2 x\)
Key Concepts
SimplificationTrigonometric FunctionsAlgebraic Manipulation
Simplification
In mathematics, simplification involves transforming an expression into its simplest form. This can often make it easier to analyze and work with. When simplifying complex expressions, especially in trigonometry, it is crucial to use known identities and algebraic manipulations to break down each part of the expression.
For instance, in the exercise
For instance, in the exercise
- The transformation from \(\frac{\tan x - \cot x}{\tan x + \cot x}\) to \(\frac{\sin x}{\cos x} - \frac{\cos x}{\sin x} \) was achieved by using the definitions of the tangent and cotangent functions.
- Further simplification involved finding a common denominator for the complex fraction, which allowed the numerator and denominator to combine more neatly.
- Ultimately, these simplifications lead to an expression of \(\sin^2 x - \cos^2 x \), which was subsequently further simplified using trigonometric identities.
Trigonometric Functions
Trigonometric functions are the building blocks of many mathematical concepts, especially in the field of trigonometry. These functions include sine, cosine, tangent, cotangent, secant, and cosecant. Understanding how these functions relate and interact with each other is essential for solving trigonometric expressions.
In this exercise:
In this exercise:
- The tangent (\(\tan x = \frac{\sin x}{\cos x}\))and cotangent (\(\cot x = \frac{\cos x}{\sin x}\)) functions were transformed into expressions involving sine and cosine.
- This transformation sets the stage for using identities and simplifications to reduce the complexity of the overall equation.
- Recognizing and applying reciprocal identities, such as \(\tan(x) = \frac{1}{\cot(x)} \) and \(\cot(x) = \frac{1}{\tan(x)} \), also ensures the manipulation steps are valid.
Algebraic Manipulation
Algebraic manipulation is the process of rearranging and restructuring equations to highlight certain desired features or simplify a solution. Understanding how to manipulate algebraically can solve equations faster and with greater insight.
In this specific task, one crucial type of algebraic manipulation was finding common denominators. This step is often used to simplify fractions by rewriting them so they have the same denominators, making the arithmetic more straightforward.
In this specific task, one crucial type of algebraic manipulation was finding common denominators. This step is often used to simplify fractions by rewriting them so they have the same denominators, making the arithmetic more straightforward.
- In the problem, the terms \(\frac{\sin x}{\cos x} - \frac{\cos x}{\sin x} \) were initially simplified by taking common denominators of \(\sin x \cos x\), combining them into a single fraction of \(\frac{\sin^2 x - \cos^2 x}{\sin x \cos x + \cos x \sin x}\).
- This allowed for the further simplification to \(\frac{\sin^2 x - \cos^2 x}{1}\), thanks to recognizing that \(\sin x \cos x + \cos x \sin x = 1\).
Other exercises in this chapter
Problem 34
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