Problem 34
Question
Express in terms of the cosine function with exponent 1. \(\sin ^{4} \frac{\theta}{2}\)
Step-by-Step Solution
Verified Answer
\(\sin^4 \frac{\theta}{2} = 1 - 2\cos^2 \frac{\theta}{2} + \cos^4 \frac{\theta}{2}\)
1Step 1: Use the Pythagorean identity
The Pythagorean identity tells us that for any angle \(\alpha\), \(\sin^2 \alpha + \cos^2 \alpha = 1\). First, express \(\sin^2 \frac{\theta}{2}\) in terms of cosine: \(\sin^2 \frac{\theta}{2} = 1 - \cos^2 \frac{\theta}{2}\).
2Step 2: Express \(\sin^4 \frac{\theta}{2}\) using Step 1
We need to express \(\sin^4 \frac{\theta}{2}\) in terms of cosine. Use the identity from Step 1, \(\sin^4 \frac{\theta}{2} = (\sin^2 \frac{\theta}{2})^2 = (1 - \cos^2 \frac{\theta}{2})^2\).
3Step 3: Expand the squared term
Expand the expression \((1 - \cos^2 \frac{\theta}{2})^2\). This gives: \[(1 - \cos^2 \frac{\theta}{2})^2 = 1 - 2\cos^2 \frac{\theta}{2} + \cos^4 \frac{\theta}{2}\]
4Step 4: Final expression in terms of cosine with exponent 1
The expression \(\sin^4 \frac{\theta}{2}\) in terms of \(\cos \frac{\theta}{2}\) is \(1 - 2\cos^2 \frac{\theta}{2} + \cos^4 \frac{\theta}{2}\).
Key Concepts
Pythagorean identitysine and cosine relationshipalgebraic manipulation
Pythagorean identity
The Pythagorean identity is a fundamental concept in trigonometry that relates the square of the sine and cosine of an angle to 1. This identity is expressed as
By rearranging the identity, you can express sine in terms of cosine, or vice versa. For example, if you solve the identity for \(\sin^2 \alpha\), you get:
Understanding how to utilize the Pythagorean identity is key for transitioning between sine and cosine in various problems.
- \(\sin^2 \alpha + \cos^2 \alpha = 1\)
By rearranging the identity, you can express sine in terms of cosine, or vice versa. For example, if you solve the identity for \(\sin^2 \alpha\), you get:
- \(\sin^2 \alpha = 1 - \cos^2 \alpha\)
Understanding how to utilize the Pythagorean identity is key for transitioning between sine and cosine in various problems.
sine and cosine relationship
Sine and cosine have a unique relationship in trigonometry, where they are both projections of the unit circle onto the y-axis and x-axis, respectively. This relationship not only underlies the Pythagorean identity but also allows for a direct transformation between the two functions.
For example:
For example:
- If you know \(\cos \alpha\), you can find \(\sin \alpha\) using the identity \(\sin^2 \alpha = 1 - \cos^2 \alpha\).
- Similarly, \(\cos^2 \alpha\) can be rewritten as \(1 - \sin^2 \alpha\).
algebraic manipulation
Algebraic manipulation involves using algebraic methods to transform expressions into a new, often simpler form. This skill is crucial in many areas of mathematics, including trigonometry.
In dealing with trigonometric identities, algebraic manipulation allows you to expand, simplify, or factor expressions to reveal insights or simplify calculations. For example, expanding \((1 - \cos^2 \frac{\theta}{2})^2\) for solving \(\sin^4 \left( \frac{\theta}{2} \right)\) in the original exercise employs:
In dealing with trigonometric identities, algebraic manipulation allows you to expand, simplify, or factor expressions to reveal insights or simplify calculations. For example, expanding \((1 - \cos^2 \frac{\theta}{2})^2\) for solving \(\sin^4 \left( \frac{\theta}{2} \right)\) in the original exercise employs:
- The distributive property: \((a - b)^2 = a^2 - 2ab + b^2\)
- Substituting terms: transforming \(1 - \cos^2 \left( \frac{\theta}{2} \right)\) to \(\sin^2 \left( \frac{\theta}{2} \right)\)
Other exercises in this chapter
Problem 34
Verify the Identity. $$\frac{\tan u-\tan v}{1+\tan u \tan v}=\frac{\cot v-\cot u}{\cot u \cot v+1}$$
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Use sum-to-product formulas to find the solutions of the equation. $$\sin 5 x-\sin x=2 \cos 3 x$$
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Exer. \(25-36:\) Verify the reduction formula. $$\tan (\pi-\theta)=-\tan \theta$$
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Find all solutions of the equation. $$2 \cos ^{2} x+\sin x=1$$
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