Problem 34
Question
Expand each expression using the properties of logarithms. \(\log _{4} \frac{x^{6}}{y^{5}}\)
Step-by-Step Solution
Verified Answer
The expanded form is \( 6 \cdot \log_{4}(x) - 5 \cdot \log_{4}(y) \).
1Step 1: Apply the Quotient Rule of Logarithms
The Quotient Rule for logarithms states that \( \log_b \left( \frac{M}{N} \right) = \log_b M - \log_b N \). Apply this rule to the given expression: \( \log_{4} \frac{x^{6}}{y^{5}} = \log_{4}(x^{6}) - \log_{4}(y^{5}) \).
2Step 2: Apply the Power Rule of Logarithms to Each Term
The Power Rule for logarithms states that \( \log_b (M^n) = n \cdot \log_b M \). Apply this to both terms in the expression: \( \log_{4}(x^{6}) = 6 \cdot \log_{4}(x) \) and \( \log_{4}(y^{5}) = 5 \cdot \log_{4}(y) \).
3Step 3: Combine the Steps
Using the results from Steps 1 and 2, the expression becomes \( 6 \cdot \log_{4}(x) - 5 \cdot \log_{4}(y) \).
Key Concepts
Quotient Rule of LogarithmsPower Rule of LogarithmsExponents in Logarithms
Quotient Rule of Logarithms
When dealing with the division of two numbers within a logarithm, we can simplify the expression using the quotients' property of logarithms. This rule is a great tool for breaking down complex expressions into simpler parts. The Quotient Rule states:
This can be especially handy when simplifying expressions or solving equations involving logarithms. For instance, if you have \( \log_4 \left( \frac{x^6}{y^5} \right) \), applying the Quotient Rule will split it into \( \log_4(x^6) - \log_4(y^5) \). This step sets the stage for further simplification using other rules like the Power Rule.
- \( \log_b \left( \frac{M}{N} \right) = \log_b M - \log_b N \)
This can be especially handy when simplifying expressions or solving equations involving logarithms. For instance, if you have \( \log_4 \left( \frac{x^6}{y^5} \right) \), applying the Quotient Rule will split it into \( \log_4(x^6) - \log_4(y^5) \). This step sets the stage for further simplification using other rules like the Power Rule.
Power Rule of Logarithms
Once we have used the Quotient Rule, we can move forward with the Power Rule of logarithms. The Power Rule is useful when a logarithm contains an exponent. It allows us to deal with such powers more easily by moving them in front of the logarithm:
With everything laid out linearly, it’s now much easier to interpret and work with these logarithmic terms. It's important to remember that the exponent comes to the front as a multiplier, making calculations more straightforward.
- \( \log_b(M^n) = n \cdot \log_b M \)
With everything laid out linearly, it’s now much easier to interpret and work with these logarithmic terms. It's important to remember that the exponent comes to the front as a multiplier, making calculations more straightforward.
Exponents in Logarithms
Exponents and logarithms often go hand in hand, especially when you're expanding or simplifying an expression. Understanding how exponents work within logarithms helps in transforming a complicated expression into a comprehensible form.
When an expression involves exponents, such as \( x^6 \) or \( y^5 \), incorporating the Power Rule allows us to bring down the exponent to the front of the logarithm. This pattern of breaking down expressions takes advantage of the properties of exponents:
When an expression involves exponents, such as \( x^6 \) or \( y^5 \), incorporating the Power Rule allows us to bring down the exponent to the front of the logarithm. This pattern of breaking down expressions takes advantage of the properties of exponents:
- Not only does it make the expression easier to handle, but it also helps set the path for further mathematical operations.
- Once simplified, you can easily add, subtract, or equate logarithmic expressions, depending on what your problem asks for.
Other exercises in this chapter
Problem 34
In \(24-35,\) for each given logarithm, find the antilogarithm, \(x .\) Write the answer to four decimal places. $$ \log x=-3 $$
View solution Problem 34
In \(27-56,\) evaluate each logarithmic expression. Show all work. $$ 3 \log _{4} \frac{1}{16} $$
View solution Problem 35
In \(33-44,\) if \(\ln 2=x\) and \(\ln 3=y,\) write each of the natural logs in terms of \(x\) and \(y\) $$ \ln 4 $$
View solution Problem 35
In \(24-35,\) for each given logarithm, find the antilogarithm, \(x .\) Write the answer to four decimal places. $$ \log x=-4 $$
View solution