Problem 34
Question
Consider the region satisfying the inequalities. Find the area of the region. $$ y \leq e^{-x}, y \geq 0, x \geq 0 $$
Step-by-Step Solution
Verified Answer
The area of the region is 1.
1Step 1: Identify the Region
Plot the inequality \(y \leq e^{-x}\) and take note of the region defined. The graph will be the exponential decay function starting from y=1 when x=0 till y approaches 0 as x increases. The region will be the area under this curve in the first quadrant because the restrictions \(y \geq 0\) and \(x \geq 0\) specify positive values of y and x.
2Step 2: Formulate integral
Since the defined region is under a curve and above the x-axis in the first quadrant, the task is to integrate the function \(y = e^{-x}\) with respect to x. The bounds of the integration will be from 0 to \(\infty\) as the region goes indefinitely along the x-axis.
3Step 3: Solve the Integral
Finally, evaluate the integral \(\int_{0}^{\infty} e^{-x} dx\). This integral yields an area of unity (1) which is the area under the entire curve of \(e^{-x}\).
Other exercises in this chapter
Problem 33
$$ \text { Evaluate the definite integral. } $$ $$ \int_{4}^{5} \frac{1}{9-x^{2}} d x $$
View solution Problem 33
Find the indefinite integral. (Hint: Integration by parts is not required for all the integrals.) $$ \int x \sqrt{x-1} d x $$
View solution Problem 34
$$ \text { Evaluate the definite integral. } $$ $$ \int_{0}^{1} \frac{3}{2 x^{2}+5 x+2} d x $$
View solution Problem 34
Find the indefinite integral. (Hint: Integration by parts is not required for all the integrals.) $$ \int \frac{x}{\sqrt{x-1}} d x $$
View solution