Problem 34
Question
Carry out the indicated operation and write your answer using positive exponents only. $$ \left(\frac{27 x^{-3} y^{2}}{8 x^{-2} y^{-5}}\right)^{1 / 3} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(\frac{3y^2}{2x^{1/3}}\).
1Step 1: Simplify the fraction inside the parentheses
To simplify the fraction, we will use the rule of exponents \(a^{-n} = \frac{1}{a^n}\):
\[
\frac{27 x^{-3} y^{2}}{8 x^{-2} y^{-5}} = \frac{27 x^{-3} y^{2}}{8 \frac{1}{x^2} \frac{1}{y^5}} = \frac{27 x^{-3} y^{2} x^2 y^5}{8}
\]
2Step 2: Apply the power (1 / 3) to each term inside the parentheses
Now apply the power of 1/3 to each term, remembering that \((a^m)^n = a^{mn}\):
\[
\left(\frac{27 x^{-3} y^{2} x^2 y^5}{8}\right)^{1/3} = \frac{27^{1/3} x^{-3(1/3)} y^{2(1/3)} x^{2(1/3)} y^{5(1/3)}}{8^{1/3}}
\]
3Step 3: Simplify the result
Simplify the expression by combining the like terms and calculating the values of exponents:
\[
\frac{3 x^{-1} y^{2/3} x^{2/3} y^{5/3}}{2} = \frac{3 (x^{-1+2/3}) (y^{2/3 + 5/3})}{2} = \frac{3x^{-1/3}y^2}{2}
\]
Since we need to write the answer using positive exponents only, we use the rule of exponents again:
\[
\frac{3x^{-1/3}y^2}{2} = \frac{3y^2}{2x^{1/3}}
\]
The final answer is:
\[
\frac{3y^2}{2x^{1/3}}
\]
Key Concepts
Simplifying FractionsPositive ExponentsRules of Exponents
Simplifying Fractions
Simplifying fractions involves making them as simple as possible. In this exercise, fractions are connected to expressions with exponents. To simplify, you apply the rules of exponents. For example, an exponent like \(a^{-n}\) translates to \(\frac{1}{a^n}\). When simplifying a fraction like \(\frac{27x^{-3}y^2}{8x^{-2}y^{-5}}\), you first transform each term using the negative exponent rule.
- Convert negative powers to positive by flipping them between numerator and denominator.
- Combine like terms by adding exponents when they have the same base.
Positive Exponents
Positive exponents represent how many times to multiply a base by itself. They're easy to handle because they follow straightforward multiplication rules. This exercise requires converting all answers into positive exponents. When dealing with positive and negative exponent combinations, remember:
- Multiply normally if the exponent is positive.
- Converts negative exponents, as they represent reciprocal or inverse values.
Rules of Exponents
The rules of exponents are vital when working with expressions that contain variables raised to powers. They provide a consistent method for simplifying and manipulating these expressions. Some key rules include:
- Product Rule: \(a^m \cdot a^n = a^{(m+n)}\)
- Quotient Rule: \(\frac{a^m}{a^n} = a^{(m-n)}\)
- Power Rule: \((a^m)^n = a^{(mn)}\)
- Zero Exponent Rule: \(a^0 = 1\)
- Negative Exponent Rule: \(a^{-n} = \frac{1}{a^n}\)
Other exercises in this chapter
Problem 34
Evaluate the expression. $$ |-1|+\sqrt{2}|-2| $$
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Solve the equation by using the quadratic formula. $$ 15-2 y^{2}=7 y $$
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Simplify the expression, writing your answer using positive exponents only. $$ \left(\frac{a^{-2}}{2 b^{2}}\right)^{-3} $$
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Solve the given equation. $$ \sqrt{2 x-3}-3=0 $$
View solution