Problem 34
Question
An \(n\)-digit number is a positive number with exactly \(n\) digits. Nine hundred distinct \(n\)-digit numbers are to be formed using only the three digits 2,5 and \(7 .\) The smallest value of \(n\) for which this is possible is (A) 6 (B) 7 (C) 8 (D) 9
Step-by-Step Solution
Verified Answer
The smallest value of \( n \) is 7.
1Step 1: Understand the Problem
We need to determine the smallest number of digits, which we will call \( n \), that a number can have such that 900 distinct numbers can be formed using the digits 2, 5, and 7.
2Step 2: Calculate the Number of Possible Combinations
Each digit in the \( n \)-digit number can be one of 2, 5, or 7. Hence, for an \( n \)-digit number, there are \( 3^n \) possible combinations that can be formed.
3Step 3: Set Up the Inequality
To find the smallest \( n \) such that at least 900 distinct numbers can be formed, solve \( 3^n \geq 900 \).
4Step 4: Evaluate the Condition for Different \( n \) Values
- For \( n = 6 \), \( 3^6 = 729 \), which is less than 900.- For \( n = 7 \), \( 3^7 = 2187 \), which is greater than 900.Thus, \( n = 7 \) is the smallest integer that satisfies \( 3^n \geq 900 \).
5Step 5: Conclusion
The smallest value of \( n \) for which 900 distinct \( n \)-digit numbers can be formed using only the digits 2, 5, and 7 is 7.
Key Concepts
Distinct NumbersDigit CombinationsInequality Problem Solving
Distinct Numbers
In the world of combinatorics, a "distinct number" refers to a number that is unique within a given set. The exercise at hand deals with forming n-digit numbers, where each entire number must be different from the others.
To achieve this, we focus on combinations of the digits 2, 5, and 7. Whenever you meet a problem involving distinct numbers, think about:
To achieve this, we focus on combinations of the digits 2, 5, and 7. Whenever you meet a problem involving distinct numbers, think about:
- Ensuring no repetitions across the whole set of numbers.
- Considering every digit's position has importance, affecting the overall identity.
Digit Combinations
Digit combinations refer to the various ways digits can be arranged to form numbers. In this problem, we are interested in how many different numbers we can form using the available digits: 2, 5, and 7. Each digit combination results in a different number.
Here’s what you should keep in mind about digit combinations:
Here’s what you should keep in mind about digit combinations:
- Each position in an n-digit number can independently be any of the given digits.
- The number of total combinations is calculated as the base number (3 in this scenario for the 3 digits) raised to the power of the number of digits (n).
Inequality Problem Solving
Inequality problem solving is about determining the range or threshold requirements that your solution must satisfy. For the case of forming distinct digit combinations, our inequality ensures that the number of distinct combinations is equal to or greater than a required figure—in this instance, 900.
Here's a simplified approach:
Here's a simplified approach:
- Set up an inequality that matches the requirements: like \(3^n \geq 900\).
- Test integer values of n to find the smallest one that meets the inequality (e.g., calculate \(3^6 = 729\) and \(3^7 = 2187\)).
- Identify the smallest n that fits, ensuring the total possible combinations meet or exceed 900.
Other exercises in this chapter
Problem 32
\(A\) set contains \((2 n+1)\) elements. The number of subsets of the set which contain at most \(n\) elements is (A) \(2^{n}\) (B) \(2^{n+1}\) (C) \(2^{2 n-1}\
View solution Problem 33
There are \(n\) concurrent lines and another line parallel to one of them. The number of different triangles that will be formed by the ( \(n+1\) ) lines, is (A
View solution Problem 35
If all permutations of the letters of the word \(A G A I N\) are arranged as in dictionary, the forty ninth word is (A) \(\mathrm{NAAGI}\) (B) \(\mathrm{NAGAI}\
View solution Problem 36
The number of ways of choosing \(n\) objects out of \((3 n+1)\) objects of which \(n\) are identical and \((2 n+1)\) are distinct, is (A) \(2^{2 n}\) (B) \(2^{2
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