Problem 34
Question
A pair of points is graphed. (a) Plot the points in a coordinate plane. (b) Find the distance between them. (c) Find the mid-point of the segment that joins them. \((5,0),(0,6)\)
Step-by-Step Solution
Verified Answer
Plot the points, the distance is \(\sqrt{61}\), midpoint is \((2.5, 3)\).
1Step 1: Understand the Points
The two points given are \((5,0)\) and \((0,6)\). These represent coordinates on the Cartesian plane, where the first number is the x-coordinate, and the second number is the y-coordinate.
2Step 2: Plot the Points
Plot the point \((5,0)\) on the x-axis where x=5 and y=0. Plot the point \((0,6)\) on the y-axis where x=0 and y=6. This creates a right triangle with the origin.
3Step 3: Use the Distance Formula
To find the distance between the points \((x_1, y_1)\) and \((x_2, y_2)\), use the distance formula: \[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\] Substitute the given points: \[d = \sqrt{(0 - 5)^2 + (6 - 0)^2} = \sqrt{(-5)^2 + 6^2} = \sqrt{25 + 36} = \sqrt{61}\]. Thus, the distance is \(\sqrt{61}\).
4Step 4: Apply the Midpoint Formula
The midpoint \((x_m, y_m)\) of a segment is found using the midpoint formula: \[x_m = \frac{x_1 + x_2}{2}, \quad y_m = \frac{y_1 + y_2}{2}\]. Substitute the given points: \[x_m = \frac{5 + 0}{2} = 2.5, \quad y_m = \frac{0 + 6}{2} = 3\]. Thus, the midpoint is \((2.5, 3)\).
Key Concepts
Distance FormulaMidpoint FormulaCartesian Plane
Distance Formula
The distance formula is a crucial tool in coordinate geometry, used to determine the length of a line segment between two points on the Cartesian plane.
It helps us quantify and understand the space between points in a plane.
The formula is derived from the Pythagorean theorem, which relates the sides of a right triangle. It allows us to find distances using coordinates.
For two points
This formula not only simplifies the task of finding distances but also helps in understanding geometric relationships between points.
In the exercise, the points
It helps us quantify and understand the space between points in a plane.
The formula is derived from the Pythagorean theorem, which relates the sides of a right triangle. It allows us to find distances using coordinates.
For two points
- \( (x_1, y_1) \) and \( (x_2, y_2) \)
- The distance \( d \) between them is
- \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
This formula not only simplifies the task of finding distances but also helps in understanding geometric relationships between points.
In the exercise, the points
- (5,0) and (0,6)
- We calculated: \[ \sqrt{(-5)^2 + 6^2} = \sqrt{61} \]
- This shows the distance between the two points to be \( \sqrt{61} \)
Midpoint Formula
The midpoint formula gives us the center point of a line segment connecting two coordinates. It's essential for bisecting a line and understanding symmetries.
If you know the coordinates of two points, finding their midpoint provides valuable information about the line segment that connects them.
For points
By finding the midpoint, you can divide a segment into two equal parts or find the line's central point easily.
It can be particularly useful for geometry problems involving bisectors or finding centroid positions.
In the given problem, for points
If you know the coordinates of two points, finding their midpoint provides valuable information about the line segment that connects them.
For points
- \( (x_1, y_1) \) and \( (x_2, y_2) \)
- The midpoint \( (x_m, y_m) \) is calculated as:
- \[ x_m = \frac{x_1 + x_2}{2}, \ y_m = \frac{y_1 + y_2}{2} \]
By finding the midpoint, you can divide a segment into two equal parts or find the line's central point easily.
It can be particularly useful for geometry problems involving bisectors or finding centroid positions.
In the given problem, for points
- (5,0) and (0,6)
- ...we got the midpoint as \( (2.5, 3) \)
Cartesian Plane
The Cartesian plane is the foundation of coordinate geometry, consisting of two number lines intersecting at right angles, creating a grid where we can plot points.
It's composed of an x-axis (horizontal line) and a y-axis (vertical line). The intersection point is called the origin, marked as \( (0,0) \).
Every point on this plane can be described using ordered pairs or coordinates, such as \( (x, y) \).
It's a fundamental aspect of graphing equations and inequalities, enabling us to represent algebraic relationships visually.
In the exercise,
It's composed of an x-axis (horizontal line) and a y-axis (vertical line). The intersection point is called the origin, marked as \( (0,0) \).
Every point on this plane can be described using ordered pairs or coordinates, such as \( (x, y) \).
- The first number indicates the position along the x-axis,
- The second number marks the position along the y-axis.
It's a fundamental aspect of graphing equations and inequalities, enabling us to represent algebraic relationships visually.
In the exercise,
- points \( (5,0) \) and \( (0,6) \) were plotted on this plane.
- Point \((5,0)\) is positioned 5 units along the x-axis and 0 units along the y-axis.
- Point \((0,6)\) is 0 units along the x-axis and 6 units along the y-axis.
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