Problem 34
Question
A metal nitrate on reaction with \(\mathrm{KI}\) gives black precipitate and with exeess \(\mathrm{KI}\) gives orange solution. The metal ion is (a) \(\mathrm{Hg}^{2+}\) (b) \(\mathrm{Pb}^{2+}\) (c) \(\mathrm{Cu}^{2+}\) (d) \(\underline{\mathrm{B} i}^{\mathrm{M}}\)
Step-by-Step Solution
Verified Answer
The metal ion is \( \mathrm{Hg}^{2+} \).
1Step 1: Identify the Reaction Conditions
We are given that a metal nitrate reacts with KI to produce a black precipitate and an orange solution when excess KI is added.
2Step 2: Analyze the Precipitate Formation
A black precipitate with KI suggests the formation of a compound like mercury(II) iodide (HgI_2), which is known to be black.
3Step 3: Consider the Color Change with Excess KI
When excess KI is added, the black precipitate (HgI_2) dissolves to form a soluble orange complex ion, [HgI_4]^{2-}, which points toward mercury ions having this characteristic behavior.
4Step 4: Compare with Other Metal Ions
Lead(II) iodide (PbI_2) forms a yellow precipitate, not black. Copper(II) and bismuth ions do not form black precipitates or orange solutions when they react with excess KI.
5Step 5: Conclusion
Based on the reaction's color changes and precipitate, the metal ion that fits the criteria is Hg^{2+}.
Key Concepts
Metal Nitrate ReactionsPrecipitate FormationComplex Ion FormationColor Change in Reactions
Metal Nitrate Reactions
When metal nitrates react with potassium iodide (KI), a fascinating array of chemical processes occur. A metal nitrate typically consists of a metal cation paired with the nitrate anion \(\text{NO}_3^-\). As it combines with KI, the iodide ion \(\text{I}^-\) tends to replace the nitrate. The resulting reaction depends significantly on the specific metal ion involved. In our case, involving mercury(II) nitrate \(\text{Hg(NO}_3)_2\), the reaction with KI sets the stage for several observable changes. Understanding how different metal nitrates behave involves recognizing their different affinities and reaction products, including precipitate formation and potential complex ion generation.
Precipitate Formation
During the reaction of mercury(II) nitrate with KI, the initial result is the formation of a black precipitate. Precipitates form as solid particles when two aqueous solutions combine to produce an insoluble compound. Here, the important player is mercury(II) iodide \(\text{HgI}_2\), which forms the characteristic black precipitate upon reaction with KI. Precipitation serves as an immediate, visually detectable sign that a chemical reaction is taking place. Not all metal ions will produce a precipitate in reaction with KI, and the color and form of the precipitate can be a helpful clue in identifying the metal involved.
Complex Ion Formation
Complex ion formation is a process where a central metal ion binds to one or more ions or molecules, resulting in a stable, complex structure. In this scenario, excess potassium iodide reacts with mercury iodide, transforming the insoluble black precipitate into a soluble orange complex ion known as \[\text{HgI}_4^{2-}\]. This process is a hallmark of the specific behavior of mercury ions, reflecting their ability to form such complexes by adding more iodide ions beyond the precipitate formation. These transformations highlight the dynamic nature of chemical reactions and the diverse capabilities of metal ions to undergo different processes under varied conditions.
Color Change in Reactions
The color changes observed in metal nitrate reactions are not just visually stunning but are crucial clues in chemical analysis. When dealing with these reactions, initial and subsequent colors can reveal important details about the ions present and their interactions. In our specific reaction, the progression from a black precipitate to an orange solution clearly indicates the initial formation of mercury iodide and its subsequent transformation into a complex ion with excess iodide ions. Such color changes serve as reliable indicators of specific reactions, helping chemists identify the substances and processes involved in a reaction. This feature is especially useful in educational settings or when performing qualitative chemical analysis.
Other exercises in this chapter
Problem 31
Identify the bactericidal antibiotic from the following (a) tetracycline (b) ofloxacin (c) erythromycin (d) chloremphenicol
View solution Problem 33
A mixture of chlorides of copper, cadmium, chromum, iron and aluminum was dissolved in water acidified with HCl and hydrogen sulphide gas was passed for suffici
View solution Problem 31
When \(\mathrm{H}_{2} \mathrm{~S}\) gas is passed through the salt solution in the presence of \(\mathrm{HCl}\), which of the following is not precipitated? (a)
View solution