Problem 34
Question
a. How many subgroups of \(Z_{5} \times Z_{6}\) are isomorphic to \(Z_{3} \times Z_{6}\) ? b. How many subgroups of \(Z \times Z\) are isomorphic to \(Z \times \mathbb{Z} ?\)
Step-by-Step Solution
Verified Answer
(a) 0; (b) Infinite.
1Step 1: Identify the Groups
The group \(Z_5 \times Z_6\) is a product of two cyclic groups of orders 5 and 6, respectively. The group \(Z_3 \times Z_6\) is a product of cyclic groups of orders 3 and 6.
2Step 2: Determine Possible Orders
For part (a), we need subgroups of \(Z_5 \times Z_6\) with the same order as \(Z_3 \times Z_6\). Calculate \(|Z_5 \times Z_6| = 30\) and \(|Z_3 \times Z_6| = 18\). For part (b), note that \(|Z \times Z| = \infty\).
3Step 3: Find Compatible Orders for Isomorphism
(a) Since \(Z_3\) and \(Z_6\) can only appear inside groups of orders divisible by 3 and 6, subgroups of \(Z_5 \times Z_6\) with order 18 are not possible. \(Z_5 \) and \(Z_6\) do not share elements of order 3. (b) \(Z \times Z\) contains all such copies of \(Z \times Z\) since any subgroup generated by two independent \(Z\) is isomorphic to \(Z \times Z\).
4Step 4: Conclusion on Isomorphic Subgroups
For (a), there are no subgroups of \(Z_5 \times Z_6\) isomorphic to \(Z_3 \times Z_6\), since no subgroup has order 18. For (b), every subgroup generated by two independent elements is isomorphic to \(Z \times Z\), indicating an infinite number.
Key Concepts
Cyclic GroupsSubgroupsIsomorphic GroupsOrders of Groups
Cyclic Groups
Cyclic groups are a fundamental concept in abstract algebra. They are groups generated by a single element, known as a generator. A cyclic group can be thought of as a 'circle' of elements where you can return to the starting element by performing the group operation repeatedly.
Here's what to remember about cyclic groups:
Here's what to remember about cyclic groups:
- They can be either finite or infinite.
- Every element in the group can be expressed as a power of the generator.
- Finite cyclic groups of order \( n \) are isomorphic to the additive group of integers modulo \( n \), denoted as \( \mathbb{Z}_n \).
- Infinite cyclic groups are isomorphic to the group of integers \( \mathbb{Z} \).
Subgroups
Subgroups are subsets of a group that themselves form a group under the same operation. This means they satisfy the group properties: closure, associativity, identity, and the existence of inverses.
Key points about subgroups:
Key points about subgroups:
- A subgroup must include the identity element of the original group.
- It must be closed under the group operation—combining two elements of the subgroup should produce another element of the subgroup.
- Any element must have an inverse in the subgroup.
- Finding subgroups of a group can help in understanding the structure and behavior of the group itself.
Isomorphic Groups
Two groups are said to be isomorphic if there is a one-to-one correspondence between their elements that respects the group operation. This relationship suggests that the two groups are structurally identical, though their elements may appear different.
Important aspects of isomorphic groups:
Important aspects of isomorphic groups:
- An isomorphism between two groups is a bijective homomorphism, meaning it's a function that is both one-to-one and onto, preserving the group operation.
- If two groups are isomorphic, they share all group properties, such as order.
- Checking if two groups are isomorphic often involves examining their generators and structure, as seen in the exercise to find out subgroups isomorphic to \(Z_3 \times Z_6\) and \(Z \times Z\).
Orders of Groups
The order of a group is a crucial concept that tells us how many elements are in the group. Understanding the order helps to determine potential subgroups and analyze the group's properties.
Here are the essentials about orders of groups:
Here are the essentials about orders of groups:
- The order of a finite group is simply the count of its elements.
- An element's order is the smallest positive integer \( n \) such that repeating the group operation \( n \) times brings you back to the identity element.
- For infinite groups like \( \mathbb{Z} \), the order is infinite.
- Understanding the order can aid in solving problems like determining possible subgroups as in the exercise above. A subgroup's order must be a divisor of the group's order.
Other exercises in this chapter
Problem 32
Mark each of the following true or false. a. If \(G_{1}\) and \(G_{2}\) are any groups, then \(G_{1} \times G_{2}\) is always isomorphic to \(G_{2} \times G_{1}
View solution Problem 33
Give an example illustrating that not every nontrivial abelian group is the internal direct product of two proper nontrivial subgroups.
View solution Problem 35
Give an example of a nontrivial group that is not of prime order and is not the internal direct product of two nontrivial subgroups.
View solution Problem 36
Mark each of the following true or false. a. Every abelian group of prime order is cyclic. b. Every abelian group of prime power order is cyclic. c. \(\mathrm{Z
View solution