Problem 34
Question
A die is rolled, Find each probability. \(P(\text { prime number })\)
Step-by-Step Solution
Verified Answer
The probability is \(\frac{1}{2}\).
1Step 1: List Possible Outcomes of a Die
A standard die has six faces, with numbers 1 through 6 on them. So the possible outcomes when a die is rolled are: 1, 2, 3, 4, 5, and 6.
2Step 2: Identify Prime Numbers
Prime numbers are numbers greater than 1 that have no divisors other than 1 and themselves. From the list of numbers on the die (1 to 6), the prime numbers are 2, 3, and 5.
3Step 3: Count Prime Number Outcomes
From the possible outcomes of rolling the die (1, 2, 3, 4, 5, 6), the prime numbers are 2, 3, and 5. So there are 3 prime number outcomes.
4Step 4: Calculate Total Number of Outcomes
Since a die has six faces, there are 6 possible outcomes when a die is rolled.
5Step 5: Calculate Probability
The probability of rolling a prime number is the number of prime number outcomes divided by the total number of outcomes. So, the probability is \(\frac{3}{6}\).
6Step 6: Simplify the Probability Fraction
Simplify \(\frac{3}{6}\) by dividing both the numerator and the denominator by their greatest common divisor, which is 3. Thus, \(\frac{3}{6} = \frac{1}{2}\).
Key Concepts
Prime Numbers OutcomesFractionsSimplification
Prime Numbers
Prime numbers are fascinating! They are numbers greater than 1 that can only be divided by 1 and themselves without leaving a remainder.
In other words, they have exactly two distinct positive divisors: 1 and the number itself.
This unique property makes them essential in various fields, including cryptography and number theory.
In other words, they have exactly two distinct positive divisors: 1 and the number itself.
This unique property makes them essential in various fields, including cryptography and number theory.
- It's important to recognize that the number 1 is not a prime number.
- Examples of prime numbers include 2, 3, 5, 7, 11, and so on.
- Notice that 2 is the only even prime number, as any other even number can be divided by 2.
Outcomes
In probability, the term "outcomes" refers to the possible results that can occur from an experiment or event.
For instance, when rolling a standard die, you can get any of the numbers from 1 to 6, describing a total of six outcomes.
For instance, when rolling a standard die, you can get any of the numbers from 1 to 6, describing a total of six outcomes.
- Each face of the die represents one unique outcome.
- This means, there's an equal chance of getting any of these numbers.
Fractions
Fractions are an essential concept in conveying probabilities. They help us express the part of a whole, which is crucial when dealing with chances and likelihoods.
A probability is often represented by a fraction, where the numerator signifies the specific number of favorable outcomes, and the denominator represents the total number of possible outcomes.
For example, when calculating the probability of rolling a prime number on a die:
A probability is often represented by a fraction, where the numerator signifies the specific number of favorable outcomes, and the denominator represents the total number of possible outcomes.
For example, when calculating the probability of rolling a prime number on a die:
- The fraction started as \(\frac{3}{6}\), meaning 3 prime outcomes out of 6 total outcomes.
- It succinctly communicates the proportion of favorable outcomes relative to all possible outcomes.
Simplification
Simplification is a straightforward but significant process that involves reducing a fraction to its simplest form.
This is done by dividing both the numerator and the denominator by their greatest common factor (GCF).
In our example:
This is done by dividing both the numerator and the denominator by their greatest common factor (GCF).
In our example:
- The original fraction \(\frac{3}{6}\) was simplified by dividing both 3 (numerator) and 6 (denominator) by 3, which is their GCF.
- After simplification, we obtained \(\frac{1}{2}\), which is a clearer and more concise way to express the same probability.
Other exercises in this chapter
Problem 33
Prove that \(4+7+10+\cdots+(3 n+1)=\frac{n(3 n+5)}{2}\) for all positive integers \(n\).
View solution Problem 34
A set of 250 data values is normally distributed with a mean of 50 and a standard deviation of 5.5 What percent of the data lies between 39 and 61\(?\)
View solution Problem 34
Give a sample set of data with a variance and standard deviation of 0.
View solution Problem 34
A card is drawn from a standard deck of cards. Find each probability. \(P(\text { jack or queen })\)
View solution