Problem 34
Question
\(29-44\) Use Cramer's Rule to solve the system. $$ \left\\{\begin{array}{l}{10 x-17 y=21} \\ {20 x-31 y=39}\end{array}\right. $$
Step-by-Step Solution
Verified Answer
x = \(\frac{2}{5}\), y = -1.
1Step 1: Identify the coefficients
The given system of linear equations is \(10x - 17y = 21\) and \(20x - 31y = 39\). Identify the coefficients: \(a_1 = 10\), \(b_1 = -17\), \(c_1 = 21\); \(a_2 = 20\), \(b_2 = -31\), \(c_2 = 39\).
2Step 2: Calculate the determinant of the coefficient matrix
The determinant \(D\) of the coefficient matrix is calculated as: \[D = \begin{vmatrix} 10 & -17 \ 20 & -31 \end{vmatrix} = (10)(-31) - (-17)(20)\].
3Step 3: Simplify the determinant
Calculate the components: \((10)(-31) = -310\) and \((-17)(20) = -340\). Therefore, the determinant \(D = -310 + 340 = 30\).
4Step 4: Calculate the determinant for x (Dₓ)
Replace the x-coefficients with the constants to find \(D_{x}\):\[D_{x} = \begin{vmatrix} 21 & -17 \ 39 & -31 \end{vmatrix} = (21)(-31) - (-17)(39)\].
5Step 5: Simplify Dₓ
Calculate the components: \((21)(-31) = -651\) and \((-17)(39) = -663\). Therefore, \(D_{x} = -651 + 663 = 12\).
6Step 6: Calculate the determinant for y (Dᵧ)
Replace the y-coefficients with the constants to find \(D_{y}\):\[D_{y} = \begin{vmatrix} 10 & 21 \ 20 & 39 \end{vmatrix} = (10)(39) - (21)(20)\].
7Step 7: Simplify Dᵧ
Calculate the components: \((10)(39) = 390\) and \((21)(20) = 420\). Therefore, \(D_{y} = 390 - 420 = -30\).
8Step 8: Solve for x and y
Using Cramer's Rule, x and y can be calculated as follows:\[ x = \frac{D_{x}}{D} = \frac{12}{30} = \frac{2}{5} \]\[ y = \frac{D_{y}}{D} = \frac{-30}{30} = -1 \]
9Step 9: Verify the solution
Substitute \(x = \frac{2}{5}\) and \(y = -1\) back into the original equations to verify:For \(10x - 17y = 21\): \(10\left(\frac{2}{5}\right) + 17 = 21\). For \(20x - 31y = 39\): \(20\left(\frac{2}{5}\right) + 31 = 39\). Both checks confirm the solution.
Key Concepts
DeterminantSystem of Linear EquationsMatrix Algebra
Determinant
A determinant is a special number that can be computed from a square matrix. In the context of solving a system of linear equations using Cramer's Rule, the determinant plays a crucial role. It helps us evaluate whether a unique solution exists.
For a 2x2 matrix:
For a 2x2 matrix:
- The determinant is calculated using the formula: \(D = ad - bc\), where \(a, b, c,\) and \(d\) are the elements of the matrix.
- If the determinant is zero, the system does not have a unique solution.
- Otherwise, the determinant provides information that leads us to the solution using Cramer’s Rule.
System of Linear Equations
A system of linear equations involves finding values for variables that satisfy all equations within the system. Each equation in the system represents a line in a 2D space. In our example, the system given was:
In our problem, we used Cramer's Rule to find this solution. Cramer’s Rule can only be applied if:
- \(10x - 17y = 21\)
- \(20x - 31y = 39\)
In our problem, we used Cramer's Rule to find this solution. Cramer’s Rule can only be applied if:
- The system is square, meaning the number of equations matches the number of variables.
- The determinant of the coefficient matrix is non-zero to ensure a unique solution.
Matrix Algebra
Matrix algebra is a vital mathematical tool for handling systems of equations. In matrix form, our system of equations is represented by aligning coefficients into a matrix:The coefficients from our system:
- Matrix \(A = \begin{pmatrix} 10 & -17 \ 20 & -31 \end{pmatrix}\)
- Constant matrix \(C = \begin{pmatrix} 21 \ 39 \end{pmatrix}\)
- The determinant of the coefficient matrix helps check the existence of a unique solution.
- Replacements of columns in the matrix are done to solve for variables \(x\) and \(y\), using Cramer's Rule.
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