Problem 34
Question
\(21-44\) . Sketch the graph of the function, not by plotting points, but by starting with the graph of a standard function and applying transformations. $$ y=-5 \sqrt{x} $$
Step-by-Step Solution
Verified Answer
Reflect and stretch \( y=\sqrt{x} \) to draw \( y=-5\sqrt{x} \).
1Step 1: Understand the Standard Function
The given function is a transformation of the square root function, which is represented as \( y = \sqrt{x} \). This function is a basic function that starts at the origin (0,0) and extends to the right, increasing slowly.
2Step 2: Apply the Vertical Stretch and Reflection
The function \( y = -5\sqrt{x} \) indicates two transformations on \( y = \sqrt{x} \). First, there is a vertical stretch by a factor of 5, which means each point on \( y = \sqrt{x} \) is moved 5 times further away from the x-axis. Second, there is a reflection across the x-axis due to the negative sign. This reflects the vertically stretched graph downward.
3Step 3: Draw the Transformed Function
Starting with the basic shape of \( y = \sqrt{x} \), apply the transformations. Reflect the initial curve across the x-axis and stretch it vertically by multiplying the \( y \)-values by 5. The resulting graph will start from the origin and curve downwards.
Key Concepts
Graph SketchingVertical StretchReflection Across AxisSquare Root Function
Graph Sketching
Sketching a graph is a way of visualizing a function without relying solely on plotted points. This approach helps us to understand the overall shape and transformations applied to a function. When sketching the graph of a transformed function, start with the graph of a standard or "parent" function. From there, apply the relevant transformations to accurately depict how the alterations affect the function's behavior and appearance. Here, we focus on the square root function and its transformations.
Vertical Stretch
A vertical stretch occurs when the output values (or y-values) of a function are multiplied by a constant factor. This transformation affects how stretched or compressed a graph appears vertically, without altering the x-values.
For instance, in the function
For instance, in the function
- The \( y = -5\sqrt{x} \) undergoes a vertical stretch by a factor of 5.
- This transformation takes the outputs (y-values) and multiplies them by 5.
- As a result, every point on the original \( y = \sqrt{x} \) graph moves 5 times further from the x-axis, making the graph steeper.
Reflection Across Axis
A reflection across an axis involves flipping a graph over a specified line. For our function, reflecting across the x-axis takes place. Reflection in this way changes the sign of the y-values, causing the graph to invert.
- In our function: the presence of a negative sign before the expression \( y = -5\sqrt{x} \) indicates a reflection over the x-axis.
- Essentially, the entire graph of \( y = 5\sqrt{x} \) flips downwards, creating a mirror image across the horizontal axis.
Square Root Function
The square root function \( y = \sqrt{x} \) serves as the basic foundation in understanding function transformations. Starting at the origin (0,0), the graph of \( y = \sqrt{x} \) extends to the right along the positive x-axis. It increases gradually, forming a curve.
- It is important to know the behavior of this parent function because it serves as the base model before any alterations.
- Understanding \( y = \sqrt{x} \)'s shape and direction allows for more straightforward application of any additional transformations, such as stretches or reflections.
Other exercises in this chapter
Problem 34
Find the functions \(f \circ g, g \circ f, f \circ f,\) and \(g \circ g\) and their domains. $$ f(x)=6 x-5, g(x)=\frac{x}{2} $$
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Sketch the graph of the piecewise defined function. \(f(x)=\left\\{\begin{array}{ll}{1} & {\text { if } x \leq 1} \\ {x+1} & {\text { if } x>1}\end{array}\right
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Use the function to evaluate the indicated expressions and simplify. $$ f(x)=6 x-18 ; \quad f\left(\frac{x}{3}\right), \frac{f(x)}{3} $$
View solution Problem 35
Find the functions \(f \circ g, g \circ f, f \circ f,\) and \(g \circ g\) and their domains. $$ f(x)=x^{2}, \quad g(x)=x+1 $$
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