Problem 332
Question
Solve the equation \((a-1) x^{2}+2(2 a+1) x+(4 a+3)=0\).
Step-by-Step Solution
Verified Answer
The solutions of the equation \((a-1) x^{2}+2(2 a+1) x+(4 a+3)=0\) in terms of \(a\) can be found by applying the quadratic formula and simplifying the resulting expression.
1Step 1: Identify the coefficients
From the given quadratic equation, we can equate it to the general form \( Ax^2 + Bx + C = 0 \). Thus, \( A = (a-1) \), \(B = 2(2a+1)\) and \(C = (4a+3)\).
2Step 2: Apply the quadratic formula
Substitute \(A\), \(B\), and \(C\) into the quadratic formula: \(x = \frac{-B \pm \sqrt{B^2 - 4AC}}{2A}\)
3Step 3: Simplify the solutions
Simplify the above expression to get the solutions of \(x\) in terms of \(a\) by performing arithmetic operations.
Key Concepts
Coefficients IdentificationQuadratic FormulaSimplification of Solutions
Coefficients Identification
When faced with a quadratic equation, the first step is to identify the coefficients. These coefficients are part of the expression that defines the equation in its standard quadratic form. A quadratic equation looks like this:
\[ Ax^2 + Bx + C = 0 \]
This is a universal format where \(A\), \(B\), and \(C\) represent constants, known as coefficients.
For the given problem, the quadratic equation
\((a-1) x^{2}+2(2 a+1) x+(4 a+3)=0\)
needs to be matched to the general form. We identify:
\[ Ax^2 + Bx + C = 0 \]
This is a universal format where \(A\), \(B\), and \(C\) represent constants, known as coefficients.
For the given problem, the quadratic equation
\((a-1) x^{2}+2(2 a+1) x+(4 a+3)=0\)
needs to be matched to the general form. We identify:
- \(A = (a-1)\), which is the coefficient of \(x^2\)
- \(B = 2(2a+1)\), which is the coefficient of \(x\)
- \(C = 4a+3\), which is the constant term
Quadratic Formula
The quadratic formula is a powerful tool used to find the solutions of a quadratic equation. Once you have identified the coefficients \(A\), \(B\), and \(C\), you can plug them into this formula:
\[ x = \frac{-B \pm \sqrt{B^2 - 4AC}}{2A} \]
This formula provides two solutions for \(x\), depending on whether you add or subtract the square root part.
For the given equation, substitute:
\[ x = \frac{-B \pm \sqrt{B^2 - 4AC}}{2A} \]
This formula provides two solutions for \(x\), depending on whether you add or subtract the square root part.
For the given equation, substitute:
- \(A = (a-1)\)
- \(B = 2(2a+1)\)
- \(C = 4a+3\)
Simplification of Solutions
After substituting the values into the quadratic formula and solving for \(x\), the work isn't complete yet. The expression you obtain often looks complicated. Simplifying this expression is a crucial step to make the solutions more understandable.
You will perform operations like:
Understanding solution simplification allows you not only to solve current problems but also to grasp the essence of quadratic equations more thoroughly.
You will perform operations like:
- Calculating the determinant \(B^2 - 4AC\)
- Simplifying the square root \(\sqrt{B^2 - 4AC}\)
- Dividing through by \(2A\)
Understanding solution simplification allows you not only to solve current problems but also to grasp the essence of quadratic equations more thoroughly.
Other exercises in this chapter
Problem 330
$$ \left(x^{2}-x-1\right)^{x^{2}-1}
View solution Problem 331
Solve the equation \(2 a(a-2) x=a-2\).
View solution Problem 333
Solve the equation \(\frac{x^{2}+1}{a^{2} x-2 a}-\frac{1}{2-a x}=\frac{x}{a}\).
View solution Problem 334
Solve the inequality \(\frac{7 x-11}{a+3}>(1+3 a) \frac{x}{4}\).
View solution