Problem 331
Question
For the following exercises, find \(f^{\prime}(x)\) for each function. $$f(x)=x^{2} e^{x}$$
Step-by-Step Solution
Verified Answer
\( f'(x) = e^x (x^2 + 2x) \)
1Step 1: Identify the Functions
We need to find the derivative of the function \( f(x) = x^2 e^x \). Here, the function is a product of two parts: \( u(x) = x^2 \) and \( v(x) = e^x \).
2Step 2: Apply the Product Rule
The product rule states that the derivative of a product \( u(x)v(x) \) is \( u'(x)v(x) + u(x)v'(x) \). We will apply this rule to find \( f'(x) \).
3Step 3: Differentiate \( u(x) = x^2 \)
Find the derivative of \( u(x) = x^2 \) with respect to \( x \). Derivative is \( u'(x) = 2x \) because the power rule \( \frac{d}{dx} x^n = nx^{n-1} \) applies here.
4Step 4: Differentiate \( v(x) = e^x \)
Find the derivative of \( v(x) = e^x \) with respect to \( x \). The derivative is \( v'(x) = e^x \) since the derivative of \( e^x \) is \( e^x \).
5Step 5: Substitute into the Product Rule Formula
Using the derivatives from Steps 3 and 4, substitute into the formula: \( f'(x) = u'(x)v(x) + u(x)v'(x) \). This gives us: \( f'(x) = 2x \cdot e^x + x^2 \cdot e^x \).
6Step 6: Simplify the Expression
The expression can be simplified by factoring out \( e^x \): \( f'(x) = e^x (2x + x^2) \). Thus, \( f'(x) = e^x (x^2 + 2x) \).
Key Concepts
Product Rule in CalculusUnderstanding the Power RuleExponential Function Differentiation
Product Rule in Calculus
The product rule is a guideline in calculus used when differentiating products of two functions. Imagine you have a function, like our example, which is composed of two separate parts multiplied together: \( u(x) \) and \( v(x) \). To find the derivative, or the rate at which the function changes, we cannot simply take the derivative of each part and multiply them. Instead, the product rule shows us how to combine the derivatives of these functions.
- The formula is: \( (uv)' = u'v + uv' \).
- This means we differentiate the first function, multiply by the second, add the original first function multiplied by the derivative of the second function.
Understanding the Power Rule
The power rule is one of the simplest rules for differentiation, yet incredibly powerful. It allows us to quickly find the derivative of functions that have the form \( x^n \), where \( n \) is any real number. The power rule states:
The power rule works seamlessly and makes differentiation straightforward because of its consistency. Whenever you see a simple power of \( x \), the power rule should immediately come to mind as a quick and reliable way to find derivatives.
- If \( f(x) = x^n \), then the derivative, \( f'(x) = nx^{n-1} \).
The power rule works seamlessly and makes differentiation straightforward because of its consistency. Whenever you see a simple power of \( x \), the power rule should immediately come to mind as a quick and reliable way to find derivatives.
Exponential Function Differentiation
Exponential functions are a unique category in mathematics characterized by their constant growth rates. A common exponential function is \( e^x \), where \( e \) is the base of natural logarithms, approximately equal to 2.718. When it comes to differentiation, exponential functions have a special property:
This self-similarity in derivatives makes them predictable and easy to work with, especially in equations and models demonstrating natural growth processes, such as populations, radioactive decay, or economic growth models.
Exponential functions exemplify how some natural laws remain unchanged, showing both elegance in mathematics and nature.
- The derivative of \( e^x \) is simply \( e^x \) itself.
This self-similarity in derivatives makes them predictable and easy to work with, especially in equations and models demonstrating natural growth processes, such as populations, radioactive decay, or economic growth models.
Exponential functions exemplify how some natural laws remain unchanged, showing both elegance in mathematics and nature.
Other exercises in this chapter
Problem 330
For the following exercises, use implicit differentiation to determine \(y^{\prime} .\) Does the answer agree with the formulas we have previously determined? $
View solution Problem 330
Use implicit differentiation to determine \(y^{\prime} .\) Does the answer agree with the formulas we have previously determined? $$ x=\tan y $$
View solution Problem 331
Find \(f^{\prime}(x)\) for each function. $$ f(x)=x^{2} e^{x} $$
View solution Problem 332
For the following exercises, find \(f^{\prime}(x)\) for each function. $$f(x)=\frac{e^{-x}}{x}$$
View solution