Problem 33
Question
Write each of the following in terms of \(i\) and simplify. For example, $$ \sqrt{-20}=i \sqrt{20}=i \sqrt{4} \sqrt{5}=2 i \sqrt{5} $$ $$\sqrt{-18}$$
Step-by-Step Solution
Verified Answer
\(\sqrt{-18} = 3i\sqrt{2}\).
1Step 1: Identify the Negative Under the Square Root
We begin by recognizing that any negative number under the square root indicates the presence of the imaginary unit \(i\), where \(i = \sqrt{-1}\). Thus, we can rewrite \(\sqrt{-18}\) as \(\sqrt{-1 \times 18}\).
2Step 2: Separate the Negative
Using the property \(\sqrt{ab} = \sqrt{a} \times \sqrt{b}\), we separate the negative from the positive component: \(\sqrt{-1 \times 18} = \sqrt{-1} \times \sqrt{18}\). Simplifying \(\sqrt{-1}\) gives us \(i\), so this becomes \(i \times \sqrt{18}\).
3Step 3: Simplify the Square Root
Now we focus on simplifying \(\sqrt{18}\). We find the prime factorization of 18, which is \(18 = 2 \times 3^2\). Thus, \(\sqrt{18} = \sqrt{2} \times \sqrt{3^2} = \sqrt{2} \times 3 = 3\sqrt{2}\).
4Step 4: Combine the Terms
Combine \(i\) with our simplified square root result. Therefore, \(i \times \sqrt{18} = i \times 3\sqrt{2} = 3i\sqrt{2}\).
Key Concepts
Imaginary UnitSquare Root SimplificationPrime Factorization
Imaginary Unit
Complex numbers are an extension of the real numbers, and they introduce the famous imaginary unit, denoted as \(i\). This unit is defined by the equation \(i = \sqrt{-1}\). Understanding \(i\) is crucial because it allows us to handle square roots of negative numbers, which don't exist in the world of real numbers. When you see a negative under a square root, you know \(i\) will play a part. For instance, the expression \(\sqrt{-9}\) becomes \(i\sqrt{9}\) or \(3i\).
- \(i^2 = -1\): Multiplying \(i\) by itself results in \(-1\).
- \(i^3 = -i\): This is because \(i^3 = i^2 \times i = -1 \times i = -i\).
- \(i^4 = 1\): Multiplying \(i\) four times returns to the start: \(i^4 = (i^2)^2 = (-1)^2 = 1\).
Square Root Simplification
Simplifying square roots is essential for making expressions more manageable. The property \(\sqrt{ab} = \sqrt{a} \times \sqrt{b}\) is a key tool. It lets us break down complex square roots into simpler components. Consider \(\sqrt{18}\). Through simplification, we factor 18 into its prime factors \(2 \times 3^2\), allowing us to rewrite it as \(\sqrt{2} \times \sqrt{3^2}\). In turn, \(\sqrt{3^2} = 3\), simplifying the expression to \(3\sqrt{2}\).Using this approach can make calculations less intimidating and more intuitive. Remember:
- Simplify within the square root to find perfect squares.
- If the expression can be broken down, it often reveals easier numbers to work with.
Prime Factorization
Prime factorization involves breaking down a number into its basic building blocks, known as prime numbers. A prime number is one that can only be divided by itself and 1. For example, the number 18 can be broken down using prime factorization: it is \(2 \times 3 \times 3\) or \(2 \times 3^2\).Understanding prime factorization helps in simplifying square roots and solving various mathematical problems:
- Identify the prime components of any number.
- Break it down into a product of prime numbers.
- Use these factors to simplify calculations, such as roots and fractions.
Other exercises in this chapter
Problem 33
Use the quadratic formula to solve each of the quadratic equations. Check your solutions by using the sum and product relationships. $$36 n^{2}-60 n+25=0$$
View solution Problem 33
Use the method of completing the square to solve each quadratic equation. $$2 x^{2}+4 x-3=0$$
View solution Problem 34
Solve each inequality. $$9 x^{2}-6 x+1 \leq 0$$
View solution Problem 34
Solve each equation. $$x^{4}-21 x^{2}+54=0$$
View solution