Problem 33
Question
write each matrix equation as a system of linear equations without matrices. $$ \left[\begin{array}{cc} 4 & -7 \\ 2 & -3 \end{array}\right]\left[\begin{array}{l} x \\ y \end{array}\right]=\left[\begin{array}{r} -3 \\ 1 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The system of linear equations is: 4x - 7y = -3 and 2x - 3y = 1
1Step 1: Understand Matrix Multiplication
In our case, matrix A is multiplied by matrix X. Matrix multiplication follows a specific rule. If A= [a ,b] and X= [x,y], then the product AX would be [ax + by]. This rule should be applied separately for each row of matrix A.
2Step 2: Apply Matrix Multiplication
Let's apply the matrix multiplication for each row of matrix A. The equations become: 4x - 7y = -3 and 2x - 3y = 1. These two equations form the system of linear equations which is the answer.
Key Concepts
Matrix MultiplicationSystems of EquationsAlgebraic Expressions
Matrix Multiplication
Matrix multiplication is a process of combining rows and columns of two matrices to produce a new matrix. It's fundamentally different from regular arithmetic multiplication. In this process, we take each row from the first matrix and each column from the second matrix and compute the sum of the products of their corresponding elements. This general rule must be applied consistently:
When you do this for a matrix equation like the one given, it means computing each element in the resulting matrix by applying these rules to every combination of rows and columns. This is what leads to our system of equations. This method allows us to simplify or solve equations in linear algebra.
- Take the elements of the row from the first matrix.
- Pair them with elements of the column from the second matrix, in order.
- Multiply each pair and add the results together.
When you do this for a matrix equation like the one given, it means computing each element in the resulting matrix by applying these rules to every combination of rows and columns. This is what leads to our system of equations. This method allows us to simplify or solve equations in linear algebra.
Systems of Equations
A system of equations is a set of equations with multiple variables. Each equation in the system shares these variables, and the goal is to find values for each variable that satisfy all equations simultaneously. These systems can often be solved using various methods such as substitution, elimination, or matrix operations such as the one shown in the example.
For instance, in the context of matrix equations, converting them into system of equations can make them easier to solve by traditional algebraic means. By breaking one matrix equation into two simple linear equations, you turn a complex problem into a manageable one. In the example provided:
For instance, in the context of matrix equations, converting them into system of equations can make them easier to solve by traditional algebraic means. By breaking one matrix equation into two simple linear equations, you turn a complex problem into a manageable one. In the example provided:
- You end up with the two equations: \(4x - 7y = -3\) and \(2x - 3y = 1\).
- This forms a system where each equation must be satisfied simultaneously.
Algebraic Expressions
An algebraic expression is a combination of numbers, variables, and operation symbols such as addition, subtraction, multiplication, and division. These expressions can represent problems and solutions by showing relationships between different quantities. In the context of linear equations, algebraic expressions form the basis of equations and systems, as they define the constraints and solutions.
In our example, the transformation from a matrix to a system leads to two expressions:
In our example, the transformation from a matrix to a system leads to two expressions:
- The expression \(4x - 7y = -3\)
- The expression \(2x - 3y = 1\)
Other exercises in this chapter
Problem 33
Use Cramer's rule to solve each system. $$ \begin{aligned}x+y+z &=0 \\\2 x-y+z &=-1 \\\\-x+3 y-z &=-8\end{aligned} $$
View solution Problem 33
Describe what happens when Gaussian elimination is used to solve an inconsistent system.
View solution Problem 33
In Exercises \(27-44,\) solve each system of equations using matrices. Use Gaussian elimination with back-substitution or Gauss-Jordan elimination. \(x+y+z=4\)
View solution Problem 34
In Exercises \(27-36,\) find (if possible): \(\begin{array}{llll}\text { a. } A B & \text { and } & \text { b. } B A\end{array}\) $$ A=\left[\begin{array}{ll} 2
View solution