Problem 33
Question
Write a quadratic equation with integer coefficients for each pair of roots. \(-2,-1\)
Step-by-Step Solution
Verified Answer
The quadratic equation is \(x^2 + 3x + 2 = 0\).
1Step 1: Define the roots
We know the roots of the quadratic equation are given as \(-2\) and \(-1\). These roots can be represented using \(x = -2\) and \(x = -1\).
2Step 2: Write the equation using the roots
The standard form of a quadratic equation with roots \(r_1\) and \(r_2\) is \((x - r_1)(x - r_2) = 0\).Plug in the given roots: \((x - (-2))(x - (-1)) = 0\),which simplifies to \((x + 2)(x + 1) = 0\).
3Step 3: Expand the expression
Now expand the expression \((x + 2)(x + 1)\):You'll perform the distribution: \(x(x + 1) + 2(x + 1)\),this results in \(x^2 + x + 2x + 2\).
4Step 4: Combine like terms
Combine the terms from the expansion: \(x^2 + x + 2x + 2\) simplifies to \(x^2 + 3x + 2\). This represents the quadratic equation with integer coefficients.
Key Concepts
Integer CoefficientsRoots of EquationsPolynomial Expansion
Integer Coefficients
In a quadratic equation, the goal is often to have integer coefficients. These are just whole numbers, including negatives. Utilizing integer coefficients makes equations simpler and more relatable when solving real-life problems.
With roots given as \(-2\) and \(-1\), we can form a quadratic expression with integer coefficients by following specific mathematical rules. In the equation \(ax^2 + bx + c = 0\), all terms \(a\), \(b\), and \(c\) should be integers, ensuring our equation remains simple to handle.
For example, with the roots \(-2\) and \(-1\), when expanded, this yields the equation \(x^2 + 3x + 2 = 0\), maintaining integer coefficients throughout the process. By keeping coefficients as integers, we simplify both the conceptual understanding and computational execution of algebraic tasks.
With roots given as \(-2\) and \(-1\), we can form a quadratic expression with integer coefficients by following specific mathematical rules. In the equation \(ax^2 + bx + c = 0\), all terms \(a\), \(b\), and \(c\) should be integers, ensuring our equation remains simple to handle.
For example, with the roots \(-2\) and \(-1\), when expanded, this yields the equation \(x^2 + 3x + 2 = 0\), maintaining integer coefficients throughout the process. By keeping coefficients as integers, we simplify both the conceptual understanding and computational execution of algebraic tasks.
Roots of Equations
The roots of an equation are the solutions where the equation equals zero. In simpler terms, they are the values of \(x\) for which the equation \(ax^2 + bx + c = 0\) holds true. They play a crucial role in formulating the equation itself.
For our exercise, the roots given are \(-2\) and \(-1\). This means if you substitute either of these numbers back into the equation, the left side will balance out to zero:
For our exercise, the roots given are \(-2\) and \(-1\). This means if you substitute either of these numbers back into the equation, the left side will balance out to zero:
- At \(-2\): \[x^2 + 3x + 2 = 0 \, simplifies \, to \, ((-2)^2 + 3(-2) + 2 = 0.)\]
- At \(-1\): \[x^2 + 3x + 2 = 0 \, simplifies \, to \, ((-1)^2 + 3(-1) + 2 = 0.)\]
Polynomial Expansion
Polynomial expansion is the method of simplifying expressions involving products of polynomials. It can seem complex, but with repetition, it becomes much more intuitive. For quadratic equations with known roots, the standard format is \((x - r_1)(x - r_2) = 0\).
Expanding these products through distribution is as follows:
We have, \( (x + 2)(x + 1) = 0\). To expand this:
Expanding these products through distribution is as follows:
We have, \( (x + 2)(x + 1) = 0\). To expand this:
- First distribute \(x\): \(x(x+1) = x^2 + x\)
- Then distribute \(+2\): \(2(x+1) = 2x + 2\)
Other exercises in this chapter
Problem 32
In \(19-34,\) write each sum or difference in terms of \(i\) $$ \frac{1}{7}+\sqrt{-\frac{1}{8}}+\frac{2}{7}-\sqrt{-\frac{1}{2}} $$
View solution Problem 32
In \(28-33,\) without graphing the parabola, describe the translation, reflection, and \(/\) or scaling that must be applied to \(y=x^{2}\) to obtain the graph
View solution Problem 33
In \(18-35,\) find each common solution algebraically. Express irrational roots in simplest radical form. $$ \begin{array}{l}{x^{2}+y^{2}=24} \\ {x+y=8}\end{arr
View solution Problem 33
In \(26-37,\) find each product. $$ (-12-2 i)(12-2 i) $$
View solution