Problem 33
Question
Verify that the given two-parameter family of functions is the general solution of the nonhomogeneous differential equation on the indicated interval. $$\begin{aligned}&y^{\prime \prime}-4 y^{\prime}+4 y=2 e^{2 x}+4 x-12\\\&y=c_{1} e^{2 x}+c_{2} x e^{2 x}+x^{2} e^{2 x}+x-2,(-\infty, \infty) \end{aligned}$$
Step-by-Step Solution
Verified Answer
The function satisfies the differential equation, confirming it is the general solution.
1Step 1: Verify the General Form of the Solution
The problem asks us to verify whether the given function \( y = c_{1} e^{2x} + c_{2} x e^{2x} + x^{2} e^{2x} + x - 2 \) is a solution to the differential equation \( y'' - 4y' + 4y = 2 e^{2x} + 4x - 12 \). The solution consists of a complementary solution to the associated homogeneous equation plus a particular solution to the nonhomogeneous equation.
2Step 2: Differentiate the Function
Compute the first derivative of the function \( y \). Use the power rule and product rule for differentiating each term:\[ y' = c_{1} (2e^{2x}) + c_{2} (2xe^{2x} + e^{2x}) + (2x^2 e^{2x} + 2 x e^{2x}) + 1 \]Simplifying gives:\[ y' = 2c_{1} e^{2x} + c_{2} (2xe^{2x} + e^{2x}) + (2xe^{2x} (x + 1) + 2 x e^{2x}) + 1 \].
3Step 3: Differentiate Again for the Second Derivative
Compute the second derivative \( y'' \):\[ y'' = c_{1} (4e^{2x}) + c_{2} (4xe^{2x} + 4e^{2x}) + (4x^2 e^{2x} + 8xe^{2x} + 4e^{2x}) \].
4Step 4: Substitute into the Differential Equation
Insert expressions for \( y, y', \) and \( y'' \) into the differential equation:\[ y'' - 4y' + 4y = (c_{1} e^{2x} + c_{2} x e^{2x} + x^2 e^{2x} + x - 2)'' - 4(c_{1} e^{2x} + c_{2} x e^{2x} + x^2 e^{2x} + x - 2)' + 4(c_{1} e^{2x} + c_{2} x e^{2x} + x^2 e^{2x} + x - 2) \].
5Step 5: Simplify and Solve
Simplify the left-hand side of the equation to match the given nonhomogeneous part of the equation (\(2 e^{2x} + 4x - 12\)). After simplifying both sides, each corresponding term on both sides of the equation should be equal, verifying that \( y = c_{1} e^{2x} + c_{2} x e^{2x} + x^2 e^{2x} + x - 2 \) is indeed a solution.
Key Concepts
Nonhomogeneous Differential EquationGeneral SolutionComplementary FunctionParticular Solution
Nonhomogeneous Differential Equation
Differential equations that include terms with no derivatives are categorized as nonhomogeneous differential equations. These equations typically take the form:\[ ay'' + by' + cy = g(x) \]where the function \( g(x) \) is known as the nonhomogeneous part or external force. This means the equation isn't strictly derivative-based and involves an additional function, affecting the system described.
Nonhomogeneous differential equations are prevalent when modeling real-world dynamics such as forced oscillations in mechanical systems or electrical circuits under external voltage sources. The presence of \( g(x) \) differentiates them from homogeneous differential equations, which have \( g(x) = 0 \).
Solving these equations involves a combination of complementary and particular solutions. This separation allows addressing each part of the equation efficiently and clearly. Understanding nonhomogeneous differential equations expands your ability to solve complex, real-world problems elegantly.
Nonhomogeneous differential equations are prevalent when modeling real-world dynamics such as forced oscillations in mechanical systems or electrical circuits under external voltage sources. The presence of \( g(x) \) differentiates them from homogeneous differential equations, which have \( g(x) = 0 \).
Solving these equations involves a combination of complementary and particular solutions. This separation allows addressing each part of the equation efficiently and clearly. Understanding nonhomogeneous differential equations expands your ability to solve complex, real-world problems elegantly.
General Solution
The general solution of a nonhomogeneous differential equation is a crucial concept encompassing all possible solutions. This solution, expressed as:\[ y = y_c + y_p \]where \( y_c \) is the complementary function and \( y_p \) is the particular solution, offers a complete framework to resolve the differential equation.
- Complementary Function (CF): Solves the associated homogeneous equation \( ay'' + by' + cy = 0 \).
- Particular Solution (PS): Solves the entire nonhomogeneous equation, including \( g(x) \).
Complementary Function
The complementary function (CF) is derived from solving the associated homogeneous equation \( ay'' + by' + cy = 0 \). This component of the general solution represents the intrinsic behavior of the equation without the influence of the external force \( g(x) \).
To find the CF, you typically:
To find the CF, you typically:
- Assume a solution of the form \( y = e^{rx} \).
- Substitute this into the homogeneous equation to find the characteristic equation.
- Solve for the roots \( r \) of the characteristic equation, which are often real or complex numbers.
- Real and distinct roots lead to solutions like \( c_1 e^{r_1 x} + c_2 e^{r_2 x} \).
- Repeated roots require multiplying solutions by increasing powers of \( x \), such as \( c_1 e^{rx} + c_2 x e^{rx} \).
- Complex roots bring sine and cosine into play, forming solutions like \( e^{ ext{Re}(r)x} (c_1 \cos( ext{Im}(r)x) + c_2 \sin( ext{Im}(r)x)) \).
Particular Solution
The particular solution (PS) focuses on satisfying the nonhomogeneous aspect of the differential equation. Unlike the complementary function, which handles the homogeneous part, the particular solution directly accounts for the influence of the non-zero function \( g(x) \).
Finding the PS involves:
Completing the particular solution effectively integrates the external influences into the differential equation, allowing it to accurately model real-world systems with forcing functions. This step is vital as it permits accurate prediction and manipulation of systems subjected to external conditions.
Finding the PS involves:
- Choosing an appropriate method, such as the method of undetermined coefficients or variation of parameters, to guess the form of \( y_p \).
- Substituting this guessed form into the nonhomogeneous differential equation.
- Solving for any unknown coefficients to fit the entire equation accurately.
Completing the particular solution effectively integrates the external influences into the differential equation, allowing it to accurately model real-world systems with forcing functions. This step is vital as it permits accurate prediction and manipulation of systems subjected to external conditions.
Other exercises in this chapter
Problem 33
Use the substitution \(x=e^{t}\) to transform the given Cauchy-Euler equation to a differential equation with constant coefficients. Solve the original equation
View solution Problem 33
Find linearly independent functions that are annihilated by the given differential operator. $$D^{3}-10 D^{2}+25 D$$
View solution Problem 34
Solve the given initial-value problem. $$\frac{d^{2} x}{d t^{2}}+\omega^{2} x=F_{0} \cos \gamma t, \quad x(0)=0, x^{\prime}(0)=0$$
View solution Problem 34
Discuss how the methods of undetermined coefficients and variation of parameters can be combined to solve the given differential equation. Carry out your ideas.
View solution