Problem 33
Question
Verify that each of the following is an identity. \(\cos (2 \pi+\theta)=\cos \theta\)
Step-by-Step Solution
Verified Answer
The identity \( \cos(2\pi + \theta) = \cos \theta \) is verified as true.
1Step 1: Understand the Identity Format
We need to verify whether the given expression \( \cos(2\pi + \theta) = \cos \theta \) is true for all values of \( \theta \). This means proving that the left side equals the right side.
2Step 2: Apply the Angle Sum Formula for Cosine
Recall the angle sum formula for cosine: \( \cos(a+b) = \cos a \cdot \cos b - \sin a \cdot \sin b \). Here, set \( a = 2\pi \) and \( b = \theta \).
3Step 3: Substitute Values for Cosine and Sine of 2π
We know that \( \cos 2\pi = 1 \) and \( \sin 2\pi = 0 \). Substitute these into the formula: \[ \cos(2\pi + \theta) = \cos 2\pi \cdot \cos \theta - \sin 2\pi \cdot \sin \theta \] This simplifies to: \[ 1 \cdot \cos \theta - 0 \cdot \sin \theta = \cos \theta \]
4Step 4: Simplify the Expression
As shown in the previous step, the expression simplifies to just \( \cos \theta \), confirming that both sides of the original equation are indeed equal.
5Step 5: Conclusion: Verification
The given identity \( \cos(2\pi + \theta) = \cos \theta \) holds true as we have shown both sides equal after simplification with trigonometric identities.
Key Concepts
Angle Sum FormulaCosine FunctionUnit CircleSine Function
Angle Sum Formula
The Angle Sum Formula is a foundational tool in trigonometry that helps us simplify the cosine and sine values when an angle is expressed as the sum of two other angles. You can think of it as a recipe for breaking down complicated angles into smaller, more manageable parts.
For the cosine of the sum of two angles, the formula is:
So whenever you're faced with an angle sum, remember this formula - it's your key to unraveling trigonometric puzzles!
For the cosine of the sum of two angles, the formula is:
- \(\cos(a+b) = \cos a \cdot \cos b - \sin a \cdot \sin b\)
So whenever you're faced with an angle sum, remember this formula - it's your key to unraveling trigonometric puzzles!
Cosine Function
The cosine function, represented as \( \cos \), is one of the primary functions in trigonometry. It quantifies the horizontal position of a point on the unit circle corresponding to a given angle.
This means when an angle \(\theta\) is plotted on the unit circle, \(\cos \theta\) provides the x-coordinate of the point on the circle.
This means when an angle \(\theta\) is plotted on the unit circle, \(\cos \theta\) provides the x-coordinate of the point on the circle.
- \(\cos(0) = 1\) because the point at an angle of \(0\) degrees (or \(0\) radians) is on the rightmost side of the unit circle.
- Similarly, \(\cos(2\pi) = 1\) since \(2\pi\) brings us full circle back to the point where we started.
Unit Circle
The unit circle is a simple yet powerful conceptual tool in trigonometry. It's a circle centered at the origin of a coordinate plane with a radius of one unit. The power of the unit circle lies in its ability to easily demonstrate the relationships between trigonometric functions and the coordinates of points on the circle.
The unit circle helps visualize how cosine and sine values are derived:
The unit circle helps visualize how cosine and sine values are derived:
- Each angle \(\theta\) on the circle corresponds to a specific point \((\cos \theta, \sin \theta)\).
- This makes it a perfect reference for understanding the periodic nature of trig functions, particularly since each full revolution (\(2\pi\) radians) around the circle brings you back to the starting point.
Sine Function
The sine function, \( \sin \), often pairs with the cosine function as a trigonometric counterpart. It measures the vertical component of an angle positioned on the unit circle. When you plot \(\theta\) on the unit circle, \(\sin \theta\) gives the y-coordinate of that point.
The sine of commonly known angles demonstrates its periodic nature:
The sine of commonly known angles demonstrates its periodic nature:
- \(\sin(0) = 0\) because the point is at the origin height-wise.
- \(\sin(2\pi) = 0\) also takes place because \(2\pi\) is a full circle completed, effectively bringing the point back to the starting horizontal line.
Other exercises in this chapter
Problem 33
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State the vertical shift, amplitude, period, and phase shift for each function. Then graph the function. $$ y=\frac{2}{5} \tan \left(6 \theta+135^{\circ}\right)
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