Problem 33
Question
Use the rate equation \(r=\frac{d}{t}\) to solve. At 2: 30 P.M. Brittney leaves her house and drives 260 miles to her sister's house. She arrives at 6: 30 p.m. a. How many hours was the drive to her sister's house? b. What was Brittney's average speed?
Step-by-Step Solution
Verified Answer
Brittney drove for 4 hours at an average speed of 65 mph.
1Step 1: Calculate Duration of the Drive
Brittney leaves at 2:30 PM and arrives at 6:30 PM. To find the duration, subtract the departure time from the arrival time: \(6:30 PM - 2:30 PM = 4\) hours. So, the drive was 4 hours long.
2Step 2: Apply the Rate Equation
We are given the distance \(d = 260\) miles. The time \(t\) has been calculated as 4 hours in Step 1. The rate equation is \(r = \frac{d}{t}\). Substitute in the known values: \(r = \frac{260}{4}\).
3Step 3: Calculate the Average Speed
Perform the division from Step 2 to find \(r\): \(r = \frac{260}{4} = 65\). So, Brittney's average speed was 65 miles per hour.
Key Concepts
Average Speed CalculationTime DurationDistance Calculation
Average Speed Calculation
Understanding how to calculate average speed is fundamental in solving problems involving movement and travel. The average speed of an object can be found using the rate equation: \( r = \frac{d}{t} \), where \( r \) is the rate or average speed, \( d \) is the distance traveled, and \( t \) is the time taken for the journey. In this equation:
- The numerator (distance \( d \)) tells us how far the object has moved.
- The denominator (time \( t \)) indicates how long it took to cover that distance.
Time Duration
Calculating the duration of a trip involves determining the amount of time taken from the beginning to the end of the journey. This is crucial for understanding how long an activity lasts. To find the time duration, simply subtract the start time from the end time. In Brittney's case:
- She began her trip at 2:30 PM and ended at 6:30 PM. - Subtracting the start time from the end time gives: \(6:30 \ \text{PM} - 2:30 \ \text{PM} = 4 \ \text{hours}\).
This calculation tells us that her drive lasted for a total of 4 hours. Make sure to keep track of AM and PM when subtracting times to avoid confusion. Properly calculating time duration is critical in applying it to other calculations, like determining the average speed.
- She began her trip at 2:30 PM and ended at 6:30 PM. - Subtracting the start time from the end time gives: \(6:30 \ \text{PM} - 2:30 \ \text{PM} = 4 \ \text{hours}\).
This calculation tells us that her drive lasted for a total of 4 hours. Make sure to keep track of AM and PM when subtracting times to avoid confusion. Properly calculating time duration is critical in applying it to other calculations, like determining the average speed.
Distance Calculation
Distance calculation is the process of finding out how far something has traveled. In problems involving moving objects, it's essential as it forms a core part of the rate equation. The formula in rate problems, \( r = \frac{d}{t} \), can be rearranged to find distance: \( d = r \times t \).
- This rearrangement allows calculation of distance if the speed and time are known.
- Knowing the distance helps in visualizing the scope of a journey or travel plan.
Other exercises in this chapter
Problem 33
Graph the points \((-3,2)\) and \((1,3),\) and draw a line through them. Use that graph to answer Problems 31-34. Does the ordered pair (4, 5) lie on this line?
View solution Problem 33
Indicate which of the given ordered pairs are solutions for each equation. $$x+y=0 \quad(0,0),(5,-5),(-3,3)$$
View solution Problem 33
Simplify each side of the following equations before applying the addition property. $$3 a+7-2 a=1$$
View solution Problem 33
Using the addition property of equality first, solve each of the following equations. $$\frac{2}{3} x-4=6$$
View solution