Problem 33
Question
Use the addition identity for the tangent to show that \(\tan (t+\pi)=\tan t\) for all \(t\) in the domain of \(\tan t\).
Step-by-Step Solution
Verified Answer
\( \tan(t+\pi) = \tan t \) by using the tangent addition identity and \( \tan \pi = 0 \).
1Step 1: Understand the Tangent Addition Identity
The tangent addition identity is given by \( \tan(a+b) = \frac{\tan a + \tan b}{1 - \tan a \tan b} \). We'll use this identity to express \( \tan(t+\pi) \).
2Step 2: Substitute into Tangent Identity
Set \( a = t \) and \( b = \pi \) in the addition identity: \( \tan(t+\pi) = \frac{\tan t + \tan \pi}{1 - \tan t \tan \pi} \).
3Step 3: Evaluate \( \tan \pi \)
Recall that \( \tan \pi = 0 \). Substitute this into the equation to get: \( \tan(t+\pi) = \frac{\tan t + 0}{1 - \tan t \cdot 0} = \frac{\tan t}{1} = \tan t \).
4Step 4: Conclusion
Thus, we have shown that \( \tan(t+\pi) = \tan t \) using the tangent addition identity.
Key Concepts
Trigonometric FunctionsTangent Function PropertyMathematical Proof
Trigonometric Functions
Trigonometric functions are essential in mathematics, especially when dealing with angles and periodic phenomena. The primary trigonometric functions are sine, cosine, and tangent. These functions help to relate the angles of a triangle to its side lengths. They are also used in various fields, such as physics, engineering, and computer science.
Let's dive a bit deeper into each:
Let's dive a bit deeper into each:
- Sine (\(\sin\)): This function relates the opposite side of a right triangle to its hypotenuse. The sine function is periodic with a period of \(2\pi\).
- Cosine (\(\cos\)): This function attaches the length of the adjacent side to the hypotenuse. Like sine, cosine has a period of \(2\pi\).
- Tangent (\(\tan\)): It is the ratio of the sine function to the cosine function (i.e., \(\tan \theta = \frac{\sin \theta}{\cos \theta}\)). This function is periodic with a period of \(\pi\).
Tangent Function Property
The tangent function has unique properties that distinguish it from sine and cosine. One of these key properties is its periodicity, which means that it repeats its values at regular intervals. The periodicity of the tangent function is \(\pi\), which results from its definition as the ratio of sine and cosine.
Here are some important properties:
Here are some important properties:
- The period of \(\tan \theta\) is \(\pi\).
- The tangent function is undefined at \(\theta = \frac{(2n+1)\pi}{2}\), where \(n\) is any integer, due to the cosine function being zero, causing a division by zero.
- Tangent's symmetry is around the origin, making it an odd function. This means \(\tan(-\theta) = -\tan(\theta)\).
Mathematical Proof
When diving into mathematical proofs, the goal is to start with known equations or identities and transform them step-by-step into the desired result. In the case of the tangent addition identity, we use the formula:\[ \tan(a+b) = \frac{\tan a + \tan b}{1 - \tan a \tan b} \]
To prove the statement \(\tan(t+\pi) = \tan t\), we follow these logical steps:
To prove the statement \(\tan(t+\pi) = \tan t\), we follow these logical steps:
- Step 1: Use the tangent addition identity and set \(a = t\) and \(b = \pi\).
- Step 2: Substitute into the identity: \(\tan(t+\pi) = \frac{\tan t + \tan \pi}{1 - \tan t\tan \pi}\)
- Step 3: Evaluate \(\tan \pi\), knowing the function has a value of zero at \(\pi\).
- Step 4: The expression simplifies as \(\tan(t+\pi) = \frac{\tan t}{1} = \tan t\).
Other exercises in this chapter
Problem 32
Find all the values of \(x\) that satisfy at least one of the two inequalities. (a) \(2 x-7>1\) or \(2 x+13\)
View solution Problem 32
Change each rational number to a decimal by performing long division. \(\frac{2}{7}\)
View solution Problem 33
In Problems \(29-34\), find an equation for each line. Then write your answer in the form \(A x+B y+C=0\). Through \((2,3)\) and \((4,8)\)
View solution Problem 33
The magnitude \(M\) of an earthquake on the Richter scale is $$ M=0.67 \log _{10}(0.37 E)+1.46 $$ where E is the energy of the earthquake in kilowatt-hours. Fin
View solution