Problem 33
Question
Use series to evaluate the limits. \begin{equation} \lim _{y \rightarrow 0} \frac{y-\tan ^{-1} y}{y^{3}} \end{equation}
Step-by-Step Solution
Verified Answer
The limit is \(\frac{1}{3}\).
1Step 1: Expand \\(y- an^{-1} y\\) Using Series
The first step is to recall the series expansion for the function \( an^{-1} y\) around \(y = 0\). The expansion is given by \( an^{-1} y = y - \frac{y^3}{3} + \frac{y^5}{5} - \cdots\). So we subtract this expansion from \(y\) to get:\[y - \tan^{-1} y = y - \left(y - \frac{y^3}{3} + \frac{y^5}{5} - \cdots\right) = \frac{y^3}{3} - \frac{y^5}{5} + \cdots\]
2Step 2: Simplify the Limit Expression
Substitute the series expansion from Step 1 into the limit expression:\[\lim _{y \rightarrow 0} \frac{y - \tan^{-1} y}{y^3} = \lim _{y \rightarrow 0} \frac{\frac{y^3}{3} - \frac{y^5}{5} + \cdots}{y^3}\]This simplifies to:\[\lim _{y \rightarrow 0} \left(\frac{1}{3} - \frac{y^2}{5} + \cdots\right)\]
3Step 3: Evaluate the Limit as \\(y ightarrow 0\\)
As \(y\) approaches 0, the higher order terms (such as \(-\frac{y^2}{5}\) and beyond) approach 0, leaving us with:\[\frac{1}{3}\]Thus, the limit evaluates to \(\frac{1}{3}\).
Key Concepts
Series ExpansionTaylor SeriesInverse Trigonometric Functions
Series Expansion
Series expansion is a mathematical technique used to represent functions as infinite sums of simpler terms. It's particularly useful around points where the function is defined, often called the "expansion point." For functions that involve complex expressions, series expansion helps in simplifying calculations by approximating complex functions with polynomial terms.
In the context of inverse trigonometric functions like \(\tan^{-1} y\), series expansions allow us to have an alternative representation of the function that is easier to handle arithmetically. When \(y\) is near zero, the function \(\tan^{-1} y\) can be expanded into a series like this:
For small values of \(y\), only the first few terms significantly contribute to the value of the function, which simplifies calculations in evaluating limits.
In the context of inverse trigonometric functions like \(\tan^{-1} y\), series expansions allow us to have an alternative representation of the function that is easier to handle arithmetically. When \(y\) is near zero, the function \(\tan^{-1} y\) can be expanded into a series like this:
- \(\tan^{-1} y = y - \frac{y^3}{3} + \frac{y^5}{5} - \cdots\)
For small values of \(y\), only the first few terms significantly contribute to the value of the function, which simplifies calculations in evaluating limits.
Taylor Series
The Taylor series is a specific type of series expansion that expresses a function as an infinite sum of terms calculated from the values of its derivatives at a single point. Taylor series are invaluable because they allow complex functions to be expressed in the simplest form possible for a specified neighborhood around a point.
Given a function \(f(y)\), its Taylor series around zero (often referred to as the Maclaurin series in this case) is given by:
Given a function \(f(y)\), its Taylor series around zero (often referred to as the Maclaurin series in this case) is given by:
- \(f(y) = f(0) + f'(0)y + \frac{f''(0)y^2}{2!} + \frac{f'''(0)y^3}{3!} + \cdots\)
- \(\tan^{-1} y = y - \frac{y^3}{3} + \frac{y^5}{5} - \cdots\)
Inverse Trigonometric Functions
Inverse trigonometric functions are those functions that reverse the action of the standard trigonometric functions like sine, cosine, and tangent. For example, the inverse tangent function, denoted \(\tan^{-1} y\), provides the angle whose tangent is \(y\). These functions are particularly significant in finding angles based on trigonometric ratios.
Inverse functions are useful in various mathematical fields such as calculus, allowing for the integration and differentiation of trigonometric functions. Specifically:
In calculus problems, such as limit evaluation, these expanded forms make it easier to simplify expressions and evaluate terms that contribute insignificantly at approaching limit points.
Inverse functions are useful in various mathematical fields such as calculus, allowing for the integration and differentiation of trigonometric functions. Specifically:
- \(\tan^{-1} y = y - \frac{y^3}{3} + \frac{y^5}{5} - \cdots\)
In calculus problems, such as limit evaluation, these expanded forms make it easier to simplify expressions and evaluate terms that contribute insignificantly at approaching limit points.
Other exercises in this chapter
Problem 32
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