Problem 33
Question
Use a pattern to factor. Check. Identify any prime polynomials. $$ x^{18}-y^{50} $$
Step-by-Step Solution
Verified Answer
The factors are \((x^9 - y^{25})(x^9 + y^{25})\). Both are prime polynomials.
1Step 1: Identify the Pattern
Recognize that the given expression is in the form of the difference of two powers, which can be expressed as \(a^n - b^m\). For the given polynomial, \(a = x^9\) and \(b = y^{25}\), resulting in the form \((x^9)^2 - (y^{25})^2\).
2Step 2: Apply the Difference of Squares Formula
Use the difference of squares formula, \(a^2 - b^2 = (a - b)(a + b)\), to factor the expression. Substituting \(a = x^9\) and \(b = y^{25}\), the expression becomes: \( (x^9 - y^{25})(x^9 + y^{25}) \).
3Step 3: Check for Prime Polynomials
Next, check each factor to see if they can be factored further. The factors \(x^9 - y^{25}\) and \(x^9 + y^{25}\) cannot be factored further using standard factoring techniques for polynomials, and both are considered prime polynomials.
Key Concepts
Difference of SquaresPrime PolynomialsAlgebraic Expressions
Difference of Squares
The difference of squares is a common algebraic expression. It appears in the form \(a^2 - b^2\). You can factor it using the formula \(a^2 - b^2 = (a - b)(a + b)\). This formula is useful for simplifying polynomials.
When you see \(a^2 - b^2\), think of it as finding two terms that, when multiplied together, produce the original expression.
For example, if you have \(x^{18} - y^{50}\), you can rewrite it using smaller powers: \(a = x^9\) and \(b = y^{25}\). This turns the original expression into \((x^9)^2 - (y^{25})^2\).
Using the difference of squares formula, you can now factor it as: \((x^9 - y^{25})(x^9 + y^{25})\). This makes complex expressions more manageable.
When you see \(a^2 - b^2\), think of it as finding two terms that, when multiplied together, produce the original expression.
For example, if you have \(x^{18} - y^{50}\), you can rewrite it using smaller powers: \(a = x^9\) and \(b = y^{25}\). This turns the original expression into \((x^9)^2 - (y^{25})^2\).
Using the difference of squares formula, you can now factor it as: \((x^9 - y^{25})(x^9 + y^{25})\). This makes complex expressions more manageable.
Prime Polynomials
A prime polynomial cannot be factored using standard algebraic methods. This means you cannot break it down further into simpler factors.
To determine if a polynomial is prime, you try to factor it. If it doesn’t work, the polynomial is prime.
In our example, \(x^9 - y^{25}\) and \(x^9 + y^{25}\) are both prime polynomials. We know this because no further factoring is possible using common techniques such as difference of squares or other factoring formulas.
Recognizing prime polynomials helps in knowing when you're done with factoring.
To determine if a polynomial is prime, you try to factor it. If it doesn’t work, the polynomial is prime.
In our example, \(x^9 - y^{25}\) and \(x^9 + y^{25}\) are both prime polynomials. We know this because no further factoring is possible using common techniques such as difference of squares or other factoring formulas.
Recognizing prime polynomials helps in knowing when you're done with factoring.
Algebraic Expressions
An algebraic expression is a combination of numbers, variables, and operators (such as +, -, *, and /).
Polynomials are a type of algebraic expression that include terms with variables raised to whole number exponents.
For example, \(x^{18} - y^{50}\) is an algebraic expression and specifically a polynomial. To factor polynomials, we use patterns and mathematical rules.
Factoring helps simplify algebraic expressions and solve equations. It breaks down complicated expressions into more manageable parts.
Learning different factoring methods allows us to handle a wide range of algebraic expressions effectively.
Polynomials are a type of algebraic expression that include terms with variables raised to whole number exponents.
For example, \(x^{18} - y^{50}\) is an algebraic expression and specifically a polynomial. To factor polynomials, we use patterns and mathematical rules.
Factoring helps simplify algebraic expressions and solve equations. It breaks down complicated expressions into more manageable parts.
Learning different factoring methods allows us to handle a wide range of algebraic expressions effectively.
Other exercises in this chapter
Problem 33
Explain why the solutions of the equation \(2(x+5)(x-1)=0\) are the same as the solutions of the equation \((2 x+10)(x-1)=0\).
View solution Problem 33
Factor completely. Identify any prime polynomials. $$ 18 y^{2}+75 y+45 $$
View solution Problem 33
Use the \(a c\) method to factor. Check the factoring. Identify any prime polynomials. $$ 3 u^{2}+14 u+8 $$
View solution Problem 34
The equation \(x(x-9)(x-9)=0\) has three factors. However, it has only two solutions. Explain why.
View solution