Problem 33
Question
The structure of iron pentacarbonyl is (a) square planar (b) trigonal bipyramid (c) triangular (d) none
Step-by-Step Solution
Verified Answer
The structure of iron pentacarbonyl is a trigonal bipyramid (b).
1Step 1: Understanding the Problem
We need to determine the molecular geometry of iron pentacarbonyl. Iron pentacarbonyl has the chemical formula Fe(CO)_5, where iron is bonded to five carbon monoxide (CO) ligands.
2Step 2: Investigating Molecular Shape
Iron pentacarbonyl is a coordination complex. To determine the geometry, we consider the coordination number and electron geometry around the central atom, iron.
3Step 3: Analyzing Electron Pair Geometry
The coordination number of the central atom, iron, in Fe(CO)_5 is 5 because it is bonded to five CO ligands. According to the VSEPR theory, a neutral complex with a coordination number of 5 typically has a trigonal bipyramidal geometry.
4Step 4: Matching Geometry to Options
Among the given options, a trigonal bipyramidal geometry corresponds to option (b), which is the correct description of the molecular geometry of iron pentacarbonyl.
Key Concepts
Coordination ComplexVSEPR TheoryTrigonal BipyramidalIron Pentacarbonyl
Coordination Complex
A coordination complex is a fascinating concept in chemistry where a central atom—often a metal—binds to a group of molecules or ions, forming a distinct entity. This bonded group, known as ligands, surround the metal atom, creating a unique arrangement. In the case of iron pentacarbonyl, the central metal is iron, while the ligands are carbon monoxide molecules. Coordination complexes have diverse applications, from industrial catalysis to biological processes. Each complex's structure depends on factors such as the size, charge, and electron configuration of the metal, as well as the nature of the ligands.
- Central atom: A metal, here it's iron.
- Ligands: Molecules or ions like CO.
- Bonds: Formed through coordination bonds.
VSEPR Theory
The VSEPR (Valence Shell Electron Pair Repulsion) theory is a simple yet powerful model used to predict the shape of molecules based on electron pair interactions. It posits that electron pairs around a central atom will arrange themselves as far apart as possible to minimize repulsion, influencing the molecular geometry. For coordination complexes, like iron pentacarbonyl, VSEPR helps in determining the overall structure by considering the coordination number—the number of ligand bonds to the central atom.
- Coordination number: Indicates the number of ligand bonds.
- Electron pair repulsion: Determines the spatial arrangement.
Trigonal Bipyramidal
The trigonal bipyramidal shape is one of the fundamental geometries predicted by VSEPR theory, especially for compounds with a coordination number of 5. This shape features two different positions for ligands:
- Axial positions: Two ligands are located along a vertical axis.
- Equatorial positions: Three ligands are placed in a plane perpendicular to the axis.
Iron Pentacarbonyl
Iron pentacarbonyl, with the formula Fe(CO)_5, serves as a classic example of a coordination complex with a trigonal bipyramidal geometry. It consists of an iron atom at the center bound to five CO ligands. This unique arrangement results in a well-defined molecular shape, crucial for its chemical interactions and applications, such as in organic synthesis and catalysis.
- Chemical formula: Fe(CO)_5
- Geometry: Trigonal bipyramidal
Other exercises in this chapter
Problem 31
The effective atomic number (EAN) of \({ }_{24} \mathrm{Cr}\) in \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}\) is (a) 24 (b) 27 (
View solution Problem 32
The IUPAC name for \(\left[\mathrm{Be}_{4} \mathrm{O}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{6}\right]\) is (a) Basic beryllium acetate(II) (b) hexa-\mu-hexa
View solution Problem 35
The oxidation state of oxygen in \(\mathrm{O}_{2}\left[\mathrm{PtF}_{6}\right]\) is (a) \(-\frac{1 / 2}{2}\) (b) \(+2\) (c) \(+1 / 2\) (d) \(+1\)
View solution Problem 36
A \(0.01 \mathrm{M}\) complex of \(\mathrm{CoCl}_{2}\) and \(\mathrm{NH}_{3}\) (molar ratio \(1: 4\) ) is found to have effective molarity of \(0.02 \mathrm{M}\
View solution