Problem 33
Question
The matrices \(A, B, C, D, E, F, G\) and \(H\) are defined as follows. $$\begin{aligned} &A=\left[\begin{array}{rr} 2 & -5 \\ 0 & 7 \end{array}\right] \quad B=\left[\begin{array}{rrr} 3 & \frac{1}{2} & 5 \\ 1 & -1 & 3 \end{array}\right] \quad C=\left[\begin{array}{rrr} 2 & -\frac{5}{2} & 0 \\ 0 & 2 & -3 \end{array}\right]\\\ &D=\left[\begin{array}{llll} 7 & 3 \end{array}\right] \quad E=\left[\begin{array}{l} 1 \\ 2 \\ 0 \end{array}\right] \quad F=\left[\begin{array}{lll} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array}\right]\\\ &G=\left[\begin{array}{rrr} 5 & -3 & 10 \\ 6 & 1 & 0 \\ -5 & 2 & 2 \end{array}\right] \quad H=\left[\begin{array}{rr} 3 & 1 \\ 2 & -1 \end{array}\right] \end{aligned}$$ Carry out the indicated algebraic operation, or explain why it cannot be performed. (a) \(A B E\) (b) \(A H E\)
Step-by-Step Solution
VerifiedKey Concepts
Matrix Algebra
- Each element of the resulting matrix is a dot product of rows and columns from the matrices being multiplied.
- The operation is associative, meaning (\(A(BC) = (AB)C\)). However, note that it is not commutative; in other words, (\(AB eq BA\)).
Matrix Dimensions
Matrix Compatibility
- For expression \(AB\), matrix \(A\) has \(2\) columns and matrix \(B\) has \(2\) rows. Therefore, they are compatible for multiplication, resulting in a \(2 \times 3\) matrix.
- For expression \(BE\), the resultant \(AB\) was found to have \(3\) columns, and matrix \(E\) has \(3\) rows. They are compatible, leading to a \(2 \times 1\) final matrix.
- For \(AH\), both are \(2 \times 2\) matrices and multiplication is possible, but adding matrix \(E\) to this sequence as \(AHE\) fails because the resulting \(AH\) matrix needs \(2\) columns to meet \(E\)'s \(3\) rows.