Problem 33
Question
The first term of a geometric sequence is \(8,\) and the second term is \(4 .\) Find the fifth term.
Step-by-Step Solution
Verified Answer
The fifth term is \( \frac{1}{2} \).
1Step 1: Identify the First Term
The first term of the sequence is given as 8. Let's denote it by \( a_1 = 8 \).
2Step 2: Find the Common Ratio
The second term is given as 4, and using the formula for the second term \( a_2 = a_1 \cdot r \), where \( r \) is the common ratio, we have \( 4 = 8 \cdot r \). Solving for \( r \), we get \( r = \frac{1}{2} \).
3Step 3: Calculate the Fifth Term
The fifth term of a geometric sequence can be found using the formula \( a_n = a_1 \cdot r^{n-1} \). Here, \( n = 5 \), so: \[ a_5 = 8 \cdot \left( \frac{1}{2} \right)^4 = 8 \cdot \frac{1}{16} = \frac{8}{16} = \frac{1}{2}. \]
4Step 4: Validate the Calculation
Revisiting the calculation for accuracy: starting from \( a_1 = 8 \) and \( r = \frac{1}{2} \), the sequence terms are \( a_2 = 4, a_3 = 2, a_4 = 1, \) and \( a_5 = \frac{1}{2} \). This pattern confirms our calculation.
Key Concepts
Common RatioSequence Term FormulaGeometric Progression
Common Ratio
In a geometric sequence, each term after the first is found by multiplying the previous term by a constant known as the "common ratio." Imagine a series of numbers where each number builds on the last by the same multiplicative factor. This factor is what we call the common ratio, commonly denoted by the symbol \( r \).
To determine the common ratio, divide any term in the sequence by the term before it. For instance, in the sequence provided, the first term is 8 and the second term is 4. Therefore, the common ratio \( r \) is calculated as:
To determine the common ratio, divide any term in the sequence by the term before it. For instance, in the sequence provided, the first term is 8 and the second term is 4. Therefore, the common ratio \( r \) is calculated as:
- \( r = \frac{4}{8} = \frac{1}{2} \)
Sequence Term Formula
The sequence term formula provides a way to find any term in a geometric sequence without listing all the previous terms. Knowing this formula is crucial in saving time and effort, especially for sequences with a large number of terms.The general rule for the \( n \)-th term of a geometric sequence is given by:
- \( a_n = a_1 \cdot r^{n-1} \)
- \( a_n \) is the \( n \)-th term
- \( a_1 \) is the first term (8 in our case)
- \( r \) is the common ratio (\( \frac{1}{2} \) here)
- \( n \) is the position of the term you want to find
- \( a_5 = 8 \cdot \left( \frac{1}{2} \right)^4 = \frac{1}{2} \)
Geometric Progression
A geometric progression is a specific type of sequence where each term is a constant multiple of the previous one. This structure gives geometric sequences their characteristic exponential nature.
A geometric progression can be simple or complex depending on the common ratio. Here are a few patterns seen in geometric progressions:
A geometric progression can be simple or complex depending on the common ratio. Here are a few patterns seen in geometric progressions:
- If \( r = 1 \), the sequence remains constant.
- If \( r > 1 \), each term increases, leading to exponential growth.
- If \( 0 < r < 1 \), like in our exercise, the terms decrease towards zero.
Other exercises in this chapter
Problem 33
Find the 28 th term in the expansion of \((A-B)^{30}\)
View solution Problem 33
Let \(F_{n}\) be the \(n\) th term of the Fibonacci sequence. Find and prove an inequality relating \(n\) and \(F_{n}\) for natural numbers \(n .\)
View solution Problem 33
Find the first six partial sums \(S_{1}, S_{2}, S_{3}, S_{4}, S_{5}, S_{6}\) of the sequence.. $$\frac{1}{3}, \frac{1}{3^{2}}, \frac{1}{3^{3}}, \frac{1}{3^{4}},
View solution Problem 34
The 12 th term of an arithmetic sequence is \(32,\) and the fifth term is \(18 .\) Find the 20 th term.
View solution