Problem 33
Question
Solve the given equation. $$ \sqrt{3 x+1}=2 $$
Step-by-Step Solution
Verified Answer
The solution to the equation \(\sqrt{3x + 1} = 2\) is \(x = 1\).
1Step 1: Square both sides of the equation
To eliminate the square root, square both sides of the equation. This will give us:
\[
(\sqrt{3x + 1})^2 = (2)^2
\]
2Step 2: Simplify the equation
When we square the square root, it cancels out, leaving us with:
\[
3x + 1 = 4
\]
3Step 3: Isolate the variable x
Subtract 1 from both sides and then divide by 3:
\[
3x = 3 \Rightarrow x = 1
\]
The solution to the equation \(\sqrt{3x + 1} = 2\) is \(x = 1\).
Key Concepts
Solving EquationsSquare RootsLinear Equations
Solving Equations
To solve equations, we look for the value of the variable that makes the equation true. An equation is like a balance scale, so any action on one side of the equation must be done to the other side. This keeps everything balanced. For our example, \(\sqrt{3x + 1} = 2\), the goal is to find \(x\) such that when substituted back into the equation, both sides are equal. We do this in steps:
- Identifying the Equation: The equation here involves a square root, making it slightly different from simpler linear equations.
- Manipulation: Typically, squaring both sides can help remove the square root, isolating the terms with \(x\).
Square Roots
A square root is a value that, when multiplied by itself, gives the original number. In algebraic terms, if \(y^2 = x\), then \(y\) is a square root of \(x\). Square roots appear often in equations, and dealing with them typically involves:
- Understanding the Radical Notation: The symbol \(\sqrt{}\) represents the square root.
- Removing Square Roots: This usually involves squaring both sides of an equation to eliminate the square root, as seen in \((\sqrt{3x + 1})^2 = 4\).
Linear Equations
A linear equation is straightforward, typically in the form of \(ax + b = c\). They are called linear because when graphed, they make a straight line. For our problem, here's how we approached it:
- Simplification: After squaring both sides, the equation \(3x + 1 = 4\) presented a linear form.
- Solving for \(x\): We subtracted 1 from both sides, leading us to \(3x = 3\), then divided by 3 to find \(x = 1\).
Other exercises in this chapter
Problem 33
Carry out the indicated operation and write your answer using positive exponents only. $$ \left(\frac{x^{3}}{-27 x^{-6}}\right)^{-2 / 3} $$
View solution Problem 33
Simplify the expression, writing your answer using positive exponents only. $$ \left(\frac{2 u^{2} v^{3}}{3 u v}\right)^{-1} $$
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State the real number property that iustifies the statement $$ \frac{a+b}{b} \div \frac{a-b}{a b}=\frac{a(a+b)}{a-b} $$
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Perform the indicated operations and simplify. $$ (3 r+2 s)(4 r-3 s) $$
View solution