Problem 33
Question
Simplify the expression. $$ \log _{2} 64 $$
Step-by-Step Solution
Verified Answer
The simplified expression is 6.
1Step 1: Understanding Logarithm Definition
The expression \( \log_{2} 64 \) asks us to find the power to which the base 2 must be raised to yield 64. In mathematical terms, this means finding \( x \) such that \( 2^x = 64 \).
2Step 2: Express 64 as a Power of 2
64 is a power of 2. We need to express 64 as an exponent of 2. We try different powers of 2: \( 2^1 = 2 \), \( 2^2 = 4 \), \( 2^3 = 8 \), \( 2^4 = 16 \), \( 2^5 = 32 \), \( 2^6 = 64 \). Thus, we find that \( 64 = 2^6 \).
3Step 3: Calculate the Logarithm
Using the result from Step 2, substitute \( 2^6 \) for 64 in the logarithm: \( \log_{2}(64) = \log_{2}(2^6) \). By the properties of logarithms, this simplifies to \( 6 \), because the logarithm function and the exponential function are inverses.
Key Concepts
Exponential FunctionsProperties of LogarithmsPowers of 2
Exponential Functions
Exponential functions are mathematical expressions where a constant base is raised to a variable exponent. They are written in the form \( b^x \), where \( b \) is the base and \( x \) is the exponent. In the context of our exercise, the base is \( 2 \) and we're interested in expressions like \( 2^x \), where \( x \) can take various values.
Key aspects of exponential functions include:
Key aspects of exponential functions include:
- The base must be a positive real number, except for 1.
- If the exponent is positive, the function grows rapidly as \( x \) increases.
- If the exponent is negative, the function approaches zero without becoming negative, as \( x \) decreases.
Properties of Logarithms
Logarithms are the inverse of exponential functions. They provide a means to solve for unknown exponents in equations of the form \( b^x = y \). The expression \( \log_{b}(y) \) represents the exponent \( x \) that base \( b \) must be raised to, in order to produce \( y \). In the exercise, \( \log_{2}(64) \) tells us the power needed to raise \( 2 \) to get 64.
Here are some important properties of logarithms that can simplify calculations:
Here are some important properties of logarithms that can simplify calculations:
- \( \log_{b}(b^x) = x \): This tells us that the logarithm of a number raised to an exponent is the exponent itself.
- \( \log_{b}(xy) = \log_{b}(x) + \log_{b}(y) \): This property allows us to split the logarithm of a product into the sum of logarithms.
- \( \log_{b}\left(\frac{x}{y}\right) = \log_{b}(x) - \log_{b}(y) \): This enables us to express the logarithm of a quotient as the difference of logarithms.
- \( \log_{b}(x^n) = n \cdot \log_{b}(x) \): This property allows the exponent to be brought out as a multiplier, simplifying calculations.
Powers of 2
Powers of 2 are ubiquitous in both mathematics and computer science. They follow a simple pattern where each successive power is double the previous one. Understanding these is critical when dealing with binary systems and logarithms that use base 2.
The sequence of powers of 2 begins with:
The sequence of powers of 2 begins with:
- \( 2^0 = 1 \)
- \( 2^1 = 2 \)
- \( 2^2 = 4 \)
- \( 2^3 = 8 \)
- \( 2^4 = 16 \)
- \( 2^5 = 32 \)
- \( 2^6 = 64 \)
Other exercises in this chapter
Problem 32
Find \(C\) and a so that \(f(x)=C a^{x}\) satisfies the given conditions. $$ f(-1)=\frac{1}{4} \text { and } f(1)=4 $$
View solution Problem 32
Determine if \(f\) is one-to-one. You may want to graph \(y=f(x)\) and apply the horizontal line test. $$ f(x)=\frac{1}{x} $$
View solution Problem 33
Find \(C\) and a so that \(f(x)=C a^{x}\) satisfies the given conditions. $$ f(-2)=\frac{9}{2} \text { and } f(2)=\frac{1}{18} $$
View solution Problem 33
Determine if \(f\) is one-to-one. You may want to graph \(y=f(x)\) and apply the horizontal line test. $$ f(x)=3 x-x^{3} $$
View solution