Problem 33
Question
Simplify. \(\sqrt{\frac{4 r^{8}}{t^{9}}}\)
Step-by-Step Solution
Verified Answer
\( \frac{2r^4}{t^{9/2}} \)
1Step 1: Simplify the Square Root
The expression to simplify is \( \sqrt{\frac{4 r^{8}}{t^{9}}} \). First, recall the property of square roots which states \( \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} \). Applying this property:\[\sqrt{\frac{4 r^{8}}{t^{9}}} = \frac{\sqrt{4r^8}}{\sqrt{t^9}}\]
2Step 2: Simplify the Numerator's Square Root
Now, simplify \( \sqrt{4r^8} \). The square root of a product is the product of the square roots: \( \sqrt{4} \times \sqrt{r^8} \). \( \sqrt{4} = 2 \) since 2 times 2 is 4, and \( \sqrt{r^8} = r^{8/2} = r^4 \).Thus, \( \sqrt{4r^8} = 2r^4 \).
3Step 3: Simplify the Denominator's Square Root
Next, simplify \( \sqrt{t^9} \). Using the property of square roots for exponents, \( \sqrt{t^9} = t^{9/2} \).
4Step 4: Write the Simplified Expression
Combine the results from step 2 and step 3 to write the simplified expression. \[\frac{\sqrt{4r^8}}{\sqrt{t^9}} = \frac{2r^4}{t^{9/2}}\]
5Step 5: Final Simplified Expression
The expression is now simplified and can be written as: \[\frac{2r^4}{t^{4.5}}\]Or, equivalently, in fractional exponent form:\[\frac{2r^4}{t^{9/2}}\]
Key Concepts
Understanding the Property of Square RootsApplying Exponent RulesMastering Simplifying RadicalsExploring Fractional Exponents
Understanding the Property of Square Roots
Square roots have unique properties that allow us to simplify expressions effectively. One crucial property is
- If you have a square root of a fraction, it can be separated into the square root of the numerator and the square root of the denominator. For instance, if you see \( \sqrt{\frac{a}{b}} \), it can be rewritten as \( \frac{\sqrt{a}}{\sqrt{b}} \). This property helps break down complex expressions for easier computation.
Applying Exponent Rules
Exponent rules are essential for managing expressions with variables raised to powers. These rules help us manipulate and simplify terms effectively:
- Product of Powers: When multiplying like bases, add their exponents. For example, \( x^a \times x^b = x^{a+b} \).
- Power of a Power: When raising an exponent to another power, multiply the exponents. For instance, \( (x^a)^b = x^{a \cdot b} \).
- Power of a Product: Any product raised to an exponent means each factor is individually raised to that exponent: \( (ab)^c = a^c \times b^c \).
- Root as a Fractional Exponent: Any nth root of a number equals raising that number to the fraction \( \frac{1}{n} \).
Mastering Simplifying Radicals
Simplifying radicals involves breaking down a square root or any other root into its simplest form. The key is to look for perfect squares or other perfect powers within the radicand (the number inside the root) and simplify step-by-step:
- Break down the number or expression under the root into factors.
- Find any perfect squares, cubes, or higher powers present, since these can be taken out of the root.
- For numbers, identify the largest perfect square factor. For variables, use exponent rules to simplify.
Exploring Fractional Exponents
Fractional exponents transform roots into a form more convenient for algebraic manipulation. Here's how they work:
- Definition: The nth root of a number, \( x^{1/n} \), is equivalent to \( \sqrt[n]{x} \). For example, \( x^{1/2} = \sqrt{x} \).
- Combining Rules: Multiply roots using their fractional exponents. If \( x^{a/n} \times x^{b/n} \), then it equals \( x^{(a+b)/n} \).
- Simplifying Expressions: Use fractional exponents to simplify exponential and radical expressions. They make it easier to apply standard arithmetic operations.
Other exercises in this chapter
Problem 33
Solve each inequality. $$ -2+\sqrt{9-5 x} \geq 6 $$
View solution Problem 33
For Exercises 33 and \(34,\) use the following information. A women's regulation-sized basketball is slightly smaller than a men's basketball. The radius \(r\)
View solution Problem 33
Simplify. $$ \sqrt{169 x^{8} y^{4}} $$
View solution Problem 33
Determine whether each pair of functions are inverse functions. $$ \begin{array}{l}{g(x)=2 x+8} \\ {f(x)=\frac{1}{2} x-4}\end{array} $$
View solution