Problem 33
Question
Simplify each expression. Write each result using positive exponents only. $$ \left(x^{5} y^{3}\right)^{-3} $$
Step-by-Step Solution
Verified Answer
\(\frac{1}{x^{15} y^9}\)
1Step 1: Apply the Power of a Power Rule
The Power of a Power Rule states that when you raise a power to another power, you multiply the exponents. So, first, apply this rule to the expression \((x^5 y^3)^{-3}\). This results in \(x^{5 imes (-3)} y^{3 imes (-3)}\).
2Step 2: Simplify the Exponents
Multiply the exponents inside the parentheses by -3: - For \(x\): \(5 \times (-3) = -15\)- For \(y\): \(3 \times (-3) = -9\)Thus, the expression becomes \(x^{-15} y^{-9}\).
3Step 3: Rewrite with Positive Exponents
To express negative exponents as positive, recall that \(a^{-n} = \frac{1}{a^n}\). Apply this rule:- For \(x^{-15}\): \(x^{-15} = \frac{1}{x^{15}}\)- For \(y^{-9}\): \(y^{-9} = \frac{1}{y^9}\)Combine these to give \(\frac{1}{x^{15} y^9}\).
Key Concepts
Power of a Power RuleNegative ExponentsPositive Exponents
Power of a Power Rule
The Power of a Power Rule is an important concept in algebra that helps to simplify expressions where one power is raised to another power. When you encounter such situations, simply multiply the inside exponent by the outside exponent. This results in a single power with a new exponent.
For example, when we simplify \((x^5 y^3)^{-3}\), we apply this rule by multiplying each exponent inside the parentheses by -3:
For example, when we simplify \((x^5 y^3)^{-3}\), we apply this rule by multiplying each exponent inside the parentheses by -3:
- For \(x\), multiply 5 by -3 to get -15
- For \(y\), multiply 3 by -3 to get -9
Negative Exponents
Dealing with negative exponents can seem tricky, but it's easier if you remember that they represent reciprocal powers. When you see a negative exponent, think of it as taking the reciprocal of the base raised to the corresponding positive exponent.
In our example, after applying the power of a power rule, we ended up with \(x^{-15}\) and \(y^{-9}\). Here's how you convert these into something more manageable:
In our example, after applying the power of a power rule, we ended up with \(x^{-15}\) and \(y^{-9}\). Here's how you convert these into something more manageable:
- For \(x^{-15}\), it's equivalent to \(\frac{1}{x^{15}}\)
- For \(y^{-9}\), it's equivalent to \(\frac{1}{y^9}\)
Positive Exponents
A fundamental aspect of algebraic simplification is writing expressions with only positive exponents. Positive exponents are straightforward and indicate how many times a number (the base) is used as a factor.
In our task, filling in positive exponents involves transforming \(x^{-15} y^{-9}\) into its reciprocal form. By applying the relationship that \(a^{-n} = \frac{1}{a^n}\), you rewrite:
In our task, filling in positive exponents involves transforming \(x^{-15} y^{-9}\) into its reciprocal form. By applying the relationship that \(a^{-n} = \frac{1}{a^n}\), you rewrite:
- \((x^{-15})\) as \(\frac{1}{x^{15}}\)
- \((y^{-9})\) as \(\frac{1}{y^9}\)
Other exercises in this chapter
Problem 33
Subtract using a vertical format. $$ \begin{array}{r} 5 u^{5}-4 u^{2}+3 u-7 \\ -\left(3 u^{5}+6 u^{2}-8 u+2\right) \\ \hline \end{array} $$
View solution Problem 33
Mixed Practice Divide. If the divisor contains 2 or more terms, use long division. See Examples 1 through 8. $$ \frac{a^{2} b^{2}-a b^{3}}{a b} $$
View solution Problem 33
The rectangle below has width \(4 x^{2}\) feet and length \(5 x^{3}\) feet. Find its area as an expression in \(x\).
View solution Problem 33
Multiply. $$ (3 x-7 y)^{2} $$
View solution