Problem 33
Question
In \(31-39,\) write the first five terms of each sequence. $$ a_{1}=1, a_{n}=2 a_{n-1}+1 $$
Step-by-Step Solution
Verified Answer
The first five terms are 1, 3, 7, 15, 31.
1Step 1: Understanding the Sequence
We are given a recursive formula for the sequence: \(a_{1} = 1\) and \(a_{n} = 2a_{n-1} + 1\). This means each term depends on the previous term.
2Step 2: Calculate the First Term
The first term, \(a_1\), is already given as 1.
3Step 3: Calculate the Second Term
Use the recursive formula to find the second term. Substitute \(a_1\) into the formula: \[ a_2 = 2 \times a_1 + 1 = 2 \times 1 + 1 = 3 \]
4Step 4: Calculate the Third Term
Use the recursive formula with the second term to find the third term: \[ a_3 = 2 \times a_2 + 1 = 2 \times 3 + 1 = 7 \]
5Step 5: Calculate the Fourth Term
Use the recursive formula with the third term to find the fourth term: \[ a_4 = 2 \times a_3 + 1 = 2 \times 7 + 1 = 15 \]
6Step 6: Calculate the Fifth Term
Use the recursive formula with the fourth term to find the fifth term: \[ a_5 = 2 \times a_4 + 1 = 2 \times 15 + 1 = 31 \]
Key Concepts
Sequence TermsRecursive FormulaMathematical PatternsAlgebra 2
Sequence Terms
In a recursive sequence, each term is built from the previous one. This means we start with a given number, known as the first term of the sequence, and then use a specific rule to find all subsequent numbers. The term "sequence terms" refers to these individual numbers in the sequence.
For example, consider a sequence starting with a first term of 1, noted as \(a_1 = 1\). Each consecutive term \(a_n\) is calculated based on the prior term \(a_{n-1}\). In our specific problem, the recursive formula \(a_n = 2a_{n-1} + 1\) gives us each new term. By following the rule, we build the sequence term by term. This approach aids in understanding how sequences grow or change, often predicting the behavior of future terms.
For example, consider a sequence starting with a first term of 1, noted as \(a_1 = 1\). Each consecutive term \(a_n\) is calculated based on the prior term \(a_{n-1}\). In our specific problem, the recursive formula \(a_n = 2a_{n-1} + 1\) gives us each new term. By following the rule, we build the sequence term by term. This approach aids in understanding how sequences grow or change, often predicting the behavior of future terms.
Recursive Formula
The magic behind recursive sequences is the recursive formula. This formula gives us a way to find each term based on the previous one, making the sequence dynamic and often quite interesting.
The recursive formula is essential because it defines the sequence's operation — how each term links to its predecessor. Let's break down the recursive formula we have:
The recursive formula is essential because it defines the sequence's operation — how each term links to its predecessor. Let's break down the recursive formula we have:
- \(a_1 = 1\): This is called the base case or initial term.
- \(a_n = 2a_{n-1} + 1\): This shows how every term after the first is calculated.
Mathematical Patterns
Finding and understanding patterns in mathematics is crucial, especially with sequences. Patterns help us see the behavior in numbers and predict future terms without having to calculate each one manually.
With the sequence generated by our recursive formula, we observe a simple mathematical pattern. Each term seems to double the previous term and then add 1. This specific pattern, produced by the formula \(a_n = 2a_{n-1} + 1\), simplifies predictions for the next terms once the structure is recognized.
With the sequence generated by our recursive formula, we observe a simple mathematical pattern. Each term seems to double the previous term and then add 1. This specific pattern, produced by the formula \(a_n = 2a_{n-1} + 1\), simplifies predictions for the next terms once the structure is recognized.
- This doubling effect is a multiplication pattern.
- The consistent addition of 1 is an arithmetic pattern.
Algebra 2
In an Algebra 2 context, recursive sequences serve as a powerful teaching tool for understanding complex algebraic relationships. Algebra 2 expands on foundational knowledge, integrating concepts like sequences to describe real-world problems and abstract numerical ideas.
Students in Algebra 2 learn to recognize how recursive formulas provide a routine method for constructing sequences. This topic not only covers arithmetic and geometric sequences but also delves into more complex forms, such as the one highlighted in this exercise.
Students in Algebra 2 learn to recognize how recursive formulas provide a routine method for constructing sequences. This topic not only covers arithmetic and geometric sequences but also delves into more complex forms, such as the one highlighted in this exercise.
- Recursive sequences bridge earlier algebra topics with higher-level mathematics.
- They illustrate how formulas are applied in iterative procedures.
Other exercises in this chapter
Problem 32
In \(31-39,\) write the first five terms of each sequence. $$ a_{1}=1, a_{n+1}=3 a_{n} $$
View solution Problem 33
Find two geometric means between 6 and \(93.75 .\)
View solution Problem 34
Find three geometric means between 3 and 9\(\frac{13}{27}\) .
View solution Problem 34
In \(31-39,\) write the first five terms of each sequence. $$ a_{1}=-2, a_{n}=-2 a_{n-1} $$
View solution