Problem 33
Question
Graph the surfaces \(z=x^{2}+y^{2}\) and \(z=1-y^{2}\) on a common screen using the domain \(|x| \leqslant 1.2,|y| \leqslant 1.2\) and observe the curve of intersection of these surfaces. Show that the projection of this curve onto the \(x y\) -plane is an ellipse.
Step-by-Step Solution
Verified Answer
The projection of the curve of intersection onto the xy-plane is an ellipse with equation \(x^2 + 2y^2 = 1\).
1Step 1: Understand the Surfaces
The first surface, \( z = x^2 + y^2 \), is a paraboloid opening upwards. The second surface, \( z = 1 - y^2 \), is a cylinder that is parallel to the x-axis and opens downward on the y-axis.
2Step 2: Graph the Surfaces
Within the domain \(|x| \leq 1.2, |y| \leq 1.2\), graph the two surfaces. The paraboloid will create a bowl-like shape while the cylindrical surface will create a sort of "curtain" shape along the y-dimension.
3Step 3: Understand Curve of Intersection
The curve of intersection is where the two surface equations are equal. Set \(x^2 + y^2 = 1 - y^2\) to find the points (x, y, z) where the two surfaces intersect.
4Step 4: Simplify the Intersection Equation
Equalize and simplify the equations: \(x^2 + y^2 = 1 - y^2 \Rightarrow x^2 + 2y^2 = 1\). This equation \(x^2 + 2y^2 = 1\) represents the intersection in the three-dimensional space.
5Step 5: Project onto the xy-plane
For projection onto the xy-plane, consider \(x^2 + 2y^2 = 1\) as an ellipse, which is the standard form for an ellipse equation with radii \(a = 1\) and \(b = \frac{1}{\sqrt{2}}\).
6Step 6: Verify the Projection
To confirm it is an ellipse: in the equation \(\frac{x^2}{1}+\frac{y^2}{\frac{1}{2}} = 1\), this formula matches the general ellipse equation \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\), confirming that the projection is indeed an ellipse.
Key Concepts
ParaboloidEllipse ProjectionCylindrical Surface
Paraboloid
A paraboloid is a three-dimensional surface that has a distinctive bowl-like shape. If you've ever seen a satellite dish, you're already familiar with this kind of surface. In mathematical terms, a paraboloid is defined by the equation \(z = x^2 + y^2\). This means that for any value of \(x\) and \(y\), the surface will curve upwards, forming a parabolic surface.
- This paraboloid opens upwards because both \(x\) and \(y\) are squared in the equation.
- The larger the values of \(x\) and \(y\), the higher the value of \(z\), implying the surface rises as you move away from the origin.
- This type of surface is often used in physics and engineering, particularly in optics and parabolic antennas.
Ellipse Projection
An ellipse is a geometric shape that looks like an elongated circle. In this exercise, we find an ellipse projection when looking at the intersection of our surfaces from above, or onto the xy-plane. After finding the equation for the curve of intersection as \(x^2 + 2y^2 = 1\), we project this onto the xy-plane to get an ellipse.
- The equation \(x^2 + 2y^2 = 1\) can be thought of as a stretched circle.
- This equation is similar to the standard form of an ellipse \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), where \(a\) and \(b\) are the radii.
- Here, \(a = 1\) along the x-axis and \(b = \frac{1}{\sqrt{2}}\) along the y-axis.
Cylindrical Surface
A cylindrical surface is another fundamental geometric structure, commonly found in various applications like tunnels and pipes. In this exercise, we examine a cylindrical surface defined by the equation \(z = 1 - y^2\).
- This equation shows that as \(y\) changes, \(z\) will decrease, as \(y^2\) is subtracted from the constant 1.
- Unlike our paraboloid, this surface is primarily aligned along the y-axis.
- Think of it as a curtain draped along the y-dimension, curving downwards.
Other exercises in this chapter
Problem 33
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Find the unit vectors that are parallel to the tangent line to the parabola \(y=x^{2}\) at the point \((2,4)\)
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