Problem 33
Question
For metal oxides, when \(\Delta G^{\circ}\) is plotted against temperature, there is a point where the graph crosses \(\Delta G=\) zero line. Above this temperature (a) the oxide is stable (b) the oxide is unstable (c) the oxide melts (d) the oxide is reduced
Step-by-Step Solution
Verified Answer
Above this temperature, the oxide is unstable (option b).
1Step 1: Understanding Gibbs Free Energy
The change in Gibbs Free Energy (9G) determines the spontaneity of a reaction. If 9G is negative, the reaction is spontaneous, while if 9G is positive, the reaction is non-spontaneous. At 9G = 0, the system is at equilibrium.
2Step 2: Graph Analysis for Metal Oxides
In the given problem, the graph of 9G^{6B} for a metal oxide against temperature is considered. The point where the graph crosses the 9G = 0 line indicates the temperature at which the formation of the oxide is in equilibrium.
3Step 3: Temperature Implications
At temperatures below the crossover point (9G < 0), the formation of the oxide is spontaneous, making the oxide stable. Above this temperature (9G > 0), the reaction becomes non-spontaneous, meaning the oxide is not stable.
4Step 4: Selecting the Correct Option
Given the options, the correct interpretation is that above the temperature where 9G = 0, the oxide cannot form spontaneously and is therefore unstable. Hence, option (b) is the correct answer.
Key Concepts
Metal OxidesSpontaneity of ReactionsStability of OxidesTemperature and Gibbs Free Energy
Metal Oxides
Metal oxides are compounds formed when metals react with oxygen. They are typically ionic compounds and are found in various forms such as
- Iron oxide (rust)
- Aluminum oxide (found in bauxite ore)
- Copper oxide
Spontaneity of Reactions
In chemistry, a reaction's spontaneity indicates whether it will occur without additional energy. This concept is evaluated using Gibbs Free Energy, denoted as \[ \Delta G \quad (\text{Gibbs Free Energy change}) \]When
- \(\Delta G < 0\), the reaction is spontaneous.
- \(\Delta G = 0\), the system is at equilibrium (neither spontaneous nor non-spontaneous).
- \(\Delta G > 0\), the reaction is non-spontaneous.
Stability of Oxides
The stability of metal oxides is largely dependent on whether the reaction forming them is spontaneous. Stability indicates a compound's resistance to change under specific conditions.When the Gibbs Free Energy graph crosses the zero line, it marks a critical point:
- Below the line, \(\Delta G < 0\), indicating spontaneous formation, hence stable.
- Above the line, \(\Delta G > 0\), indicating non-spontaneous formation, hence unstable.
Temperature and Gibbs Free Energy
Temperature significantly influences Gibbs Free Energy and, consequently, the stability and spontaneity of metal oxide formation. As temperature fluctuates, the Gibbs Free Energy change \(\Delta G\) varies:
- Below a certain temperature, \(\Delta G\) is negative, which means spontaneous oxide formation.
- Above this temperature, \(\Delta G\) becomes positive, leading to non-spontaneous or unstable conditions for the oxide.
Other exercises in this chapter
Problem 32
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