Problem 33
Question
Find the two real-number solutions of each equation. $$ x^{2}=100 $$
Step-by-Step Solution
Verified Answer
The real-number solutions of the equation \(x^{2}=100\) are \(x1=-10\) and \(x2=10\).
1Step 1: Identify the problem
The equation \( x^{2}=100 \) is given. It's a type of quadratic equation in the format of \( x^{2}=a \) where a equals to 100. Therefore, we need to find two real solutions of this equation.
2Step 2: Find the square root of the number on the right-hand side
The square root of 100 can be found easily. \(\sqrt{100} = 10\). The square root of a number has two results, one positive and one negative.
3Step 3: Write the solutions
So, the answers to the equation \(x^{2}=100\) are \(x1 = -10\) (negative square root of 100) and \(x2 = +10\) (positive square root of 100).
Key Concepts
Real-number solutionsSquare rootsSolving equations
Real-number solutions
Quadratic equations often seek real-number solutions. These solutions are the values of the variable (usually represented as \( x \)) that satisfy the equation. Real numbers include both positive and negative numbers, zero, and fractional numbers. When dealing with quadratic equations like \( x^2 = 100 \), the task is to find all possible real solutions.
- If a quadratic equation is in the form \( x^2 = a \) where \( a \) is a positive number, it generally has two real-number solutions: one positive and one negative.
- Only positive or negative solutions indicate the direction of the real-number line they appear on.
- For equations where \( a = 0 \), the only real solution would be \( x = 0 \).
- When \( a \) is negative, real-number solutions do not exist because square roots of negative numbers are not real under typical real-number operations.
Square roots
Square roots play a crucial role in solving quadratic equations. To solve an equation like \( x^2 = a \), we need the square root of \( a \). The square root operation finds a number that, when multiplied by itself, equals \( a \).
- For positive numbers, there are two possible square roots: one positive and one negative. For \( a = 100 \), the square roots are \( +10 \) and \( -10 \).
- The square root of 100 is 10, because \( 10 \times 10 = 100 \).
- The notation \( \sqrt{a} \) refers to the principal square root, which is non-negative. The negative square root is represented as \( -\sqrt{a} \).
Solving equations
Solving equations is the process of finding values for the variable that make the equation true. For quadratic equations like \( x^2 = 100 \), the steps are straightforward yet significant.
- Identify the equation form: Recognize \( x^2 = a \) and deduce what \( a \) represents.
- Compute the square root: Find \( \sqrt{a} \) and address both the positive and negative possibilities.
- State the solutions: In our example, we find that \( x = 10 \) and \( x = -10 \) are both correct answers.
Other exercises in this chapter
Problem 33
Rationalize the denominator of each expression. Assume that all variables are positive. $$ \frac{\sqrt{3 x y^{2}}}{\sqrt{5 x y^{3}}} $$
View solution Problem 33
Simplify each number. $$(-32)^{\frac{6}{5}}$$
View solution Problem 34
Rewrite each function to make it easy to graph using transformations of its parent function. Describe the graph. \(y=\sqrt[3]{64 x+128}\)
View solution Problem 34
Solve. Check for extraneous solutions. \(3 \sqrt{2 x}-3=9\)
View solution