Problem 33
Question
Find the indicated trigonometric function values. If \(\csc \theta=\frac{2}{\sqrt{3}}\) and the terminal side of \(\theta\) lies in quadrant II, find \(\cot \theta\)
Step-by-Step Solution
Verified Answer
\( \cot \theta = -\frac{\sqrt{3}}{3} \)
1Step 1: Understand the given information
We are given that \( \csc \theta = \frac{2}{\sqrt{3}} \). The cosecant function is the reciprocal of the sine function. Thus, \( \sin \theta = \frac{\sqrt{3}}{2} \). Additionally, we know that \( \theta \) is in the second quadrant.
2Step 2: Determine the angle's sign behavior in Quadrant II
In the second quadrant, \( \sin \theta \) remains positive and \( \cos \theta \) is negative. Therefore, \( \cos \theta = -\sqrt{1 - \sin^2 \theta} \) since cosine values are negative in Quadrant II.
3Step 3: Calculate \( \cos \theta \)
Use the identity \( \sin^2 \theta + \cos^2 \theta = 1 \). Substitute \( \sin \theta = \frac{\sqrt{3}}{2} \) to find \( \cos \theta = -\sqrt{1 - \left(\frac{\sqrt{3}}{2}\right)^2} = -\sqrt{1 - \frac{3}{4}} = -\sqrt{\frac{1}{4}} = -\frac{1}{2} \).
4Step 4: Finding \( \cot \theta \)
Recall that \( \cot \theta = \frac{\cos \theta}{\sin \theta} \). Substitute the values we found: \( \cos \theta = -\frac{1}{2} \) and \( \sin \theta = \frac{\sqrt{3}}{2} \). Thus, \( \cot \theta = \frac{-\frac{1}{2}}{\frac{\sqrt{3}}{2}} = -\frac{1}{\sqrt{3}} = -\frac{\sqrt{3}}{3} \).
Key Concepts
CosecantCotangentQuadrant Analysis
Cosecant
Cosecant is one of the six fundamental trigonometric functions, and it is particularly important when dealing with right-angle triangles or the unit circle. It's often denoted as \( \csc \theta \), which stands for cosecant of an angle \( \theta \). It is the reciprocal of the sine function.
- If \( \, \sin \theta = a \), then \( \csc \theta = \frac{1}{a} \).
- To find \( \, \sin \theta \) when given \( \csc \theta \), take the reciprocal of the value.
Cotangent
Cotangent is another fundamental trigonometric function represented as \( \cot \theta \). It is defined as the reciprocal of the tangent function:
- \( \cot \theta = \frac{1}{\tan \theta} \).
- Alternatively, it can be expressed as \( \cot \theta = \frac{\cos \theta}{\sin \theta} \).
Quadrant Analysis
Quadrant analysis is essential for understanding how trigonometric functions behave in different regions of the coordinate plane. The plane is divided into four quadrants, each affecting trigonometric functions uniquely:
- Quadrant I: All trigonometric functions are positive.
- Quadrant II: Sine is positive; cosine and tangent are negative.
- Quadrant III: Tangent is positive; sine and cosine are negative.
- Quadrant IV: Cosine is positive; sine and tangent are negative.
Other exercises in this chapter
Problem 33
The measures of two sides and an angle are given. Determine whether a triangle (or two) exist, and if so, solve the triangle(s). $$a=\sqrt{2}, b=\sqrt{7}, \beta
View solution Problem 33
Use a calculator to evaluate the trigonometric functions for the indicated angle values. Round your answers to four decimal places. $$\cos 82^{\circ}$$
View solution Problem 33
Convert from radians to degrees. $$\frac{3 \pi}{8}$$
View solution Problem 34
Find the area of each triangle with measures given. $$b=9, c=10, \alpha=100^{\circ}$$
View solution