Problem 33
Question
Find each product. See Example 2. $$ \left(0.4-9 m^{2}\right)\left(0.4+9 m^{2}\right) $$
Step-by-Step Solution
Verified Answer
The product is \(0.16 - 81m^4\).
1Step 1: Identify the Expression
The expression to be multiplied is \((0.4 - 9m^2)(0.4 + 9m^2)\). This is a multiplication of two binomials that are conjugates of each other.
2Step 2: Apply the Difference of Squares Formula
Recognize that the expression is in the form \((a - b)(a + b)\), which can be simplified using the difference of squares formula: \((a - b)(a + b) = a^2 - b^2\).
3Step 3: Identify the Terms for a and b
In the expression \((0.4 - 9m^2)(0.4 + 9m^2)\), let \(a = 0.4\) and \(b = 9m^2\).
4Step 4: Square the Terms
Square both terms: Calculate \(a^2 = (0.4)^2\) and \(b^2 = (9m^2)^2\). This gives us \(a^2 = 0.16\) and \(b^2 = 81m^4\).
5Step 5: Substitute into the Formula
Substitute \(a^2\) and \(b^2\) into the difference of squares formula: \((0.4)^2 - (9m^2)^2 = 0.16 - 81m^4\).
6Step 6: Simplify the Expression
After substituting, the expression \(0.16 - 81m^4\) is already simplified, as there are no like terms to combine.
Key Concepts
Difference of SquaresBinomialsPolynomial Multiplication
Difference of Squares
Algebra can sometimes seem daunting, but understanding key patterns can make things much easier. One such useful pattern is the "Difference of Squares." This is a special formula that allows us to simplify expressions where two conjugate binomials are involved. The classic formula is:
This formula is extremely handy because it saves time and reduces the complexity of calculations. For instance, instead of multiplying out every term, recognizing the pattern lets you find the product of two expressions much more efficiently. By using difference of squares, the multiplication simplifies almost immediately to a subtraction of squared terms. Whenever working algebraically, it’s useful to be on the lookout for such patterns as they frequently appear.
- \((a - b)(a + b) = a^2 - b^2\)
This formula is extremely handy because it saves time and reduces the complexity of calculations. For instance, instead of multiplying out every term, recognizing the pattern lets you find the product of two expressions much more efficiently. By using difference of squares, the multiplication simplifies almost immediately to a subtraction of squared terms. Whenever working algebraically, it’s useful to be on the lookout for such patterns as they frequently appear.
Binomials
Binomials are at the core of many algebraic expressions. A binomial is simply a polynomial that consists of exactly two terms. For example,
Recognizing and understanding how to manipulate binomials using algebraic rules is crucial when dealing with more advanced polynomials and solving equations. As you practice with binomials, you'll become adept at spotting patterns and simplifying expressions efficiently.
- \(0.4 - 9m^2\) is a binomial
- \((a - b)\) and \((a + b)\)
Recognizing and understanding how to manipulate binomials using algebraic rules is crucial when dealing with more advanced polynomials and solving equations. As you practice with binomials, you'll become adept at spotting patterns and simplifying expressions efficiently.
Polynomial Multiplication
Polynomial multiplication underpins many algebraic processes, including the example exercise provided. When we talk about multiplying polynomials like binomials, we are essentially distributing each term across one another. This means, every term of the first polynomial multiplies with every term of the second polynomial. However, certain techniques, like recognizing the difference of squares, can drastically simplify the process.
Generally, multiplying polynomials involves using the distributive property, which may result in a large number of individual terms to simplify. But with expressions like
Generally, multiplying polynomials involves using the distributive property, which may result in a large number of individual terms to simplify. But with expressions like
- \((0.4 - 9m^2)(0.4 + 9m^2)\)
- \(0.16 - 81m^4\)
Other exercises in this chapter
Problem 32
Write number in scientific notation. \(290,000\)
View solution Problem 32
Express using positive exponents and simplify, if possible. \(7^{-1}-7^{0}\)
View solution Problem 33
Use the product rule for exponents to simplify each expression. Write the results using exponents. $$ \left(a^{2} b^{3}\right)\left(a^{3} b^{3}\right) $$
View solution Problem 33
Find the degree of each polynomial. See Example \(1 .\) $$ 3 x^{4} $$
View solution