Problem 33
Question
Find an equation of the following ellipses, assuming the center is at the origin. Sketch a graph labeling the vertices and foci. An ellipse whose major axis is on the \(x\) -axis with length 8 and whose minor axis has length 6
Step-by-Step Solution
Verified Answer
Answer: The values of \(a\) and \(b\) are 4 and 3 respectively. The equation of the ellipse is \(\frac{x^2}{16} + \frac{y^2}{9} = 1\). The coordinates of the vertices are \((-4, 0)\) and \((4, 0)\), and the coordinates of the foci are \((-\sqrt{7}, 0)\) and \((\sqrt{7}, 0)\).
1Step 1: Calculate \(a\) and \(b\) values
Half the length of the major axis is 8/2 = 4 and half the length of the minor axis is 6/2 = 3. Therefore, \(a=4\) and \(b=3\).
2Step 2: Write the equation of the ellipse
Now we can plug \(a=4\) and \(b=3\) into the ellipse equation with center at the origin: \(\frac{x^2}{4^2} + \frac{y^2}{3^2} = 1\). So the equation of the ellipse is \(\frac{x^2}{16} + \frac{y^2}{9} = 1\).
3Step 3: Find coordinates of the vertices
The vertices are located at \((\pm a, 0)\). Thus, the coordinates of the vertices are \((\pm 4, 0)\), or specifically, \((-4, 0)\) and \((4, 0)\).
4Step 4: Calculate the distance between the center and foci
To find the distance \(c\) between the center and the foci, we use the relation \(c^2 = a^2 - b^2\). So, \(c^2 = 4^2 - 3^2 = 16 - 9 = 7\), and \(c = \sqrt{7}\).
5Step 5: Find coordinates of the foci
The foci are located at \((\pm c, 0)\). Thus, the coordinates of the foci are \((\pm \sqrt{7}, 0)\), or specifically, \((-\sqrt{7}, 0)\) and \((\sqrt{7}, 0)\).
6Step 6: Sketch the graph
To sketch the graph, plot the center at the origin (0,0), and the vertices at \((-4,0)\) and \((4,0)\). Mark the foci at \((-\sqrt{7},0)\) and \((\sqrt{7},0)\). Draw the ellipse, making sure that the major axis has a length of 8 and the minor axis has a length of 6. Label the vertices and foci on the graph.
Key Concepts
Vertices and FociMajor and Minor AxesCenter at Origin
Vertices and Foci
The vertices and foci are essential parts of an ellipse, providing a clear understanding of its shape and orientation. Vertices are the points on the ellipse that lie farthest from the center along the major axis.
In our example, the major axis is along the x-axis, making the vertices
In our example, the major axis is along the x-axis, making the vertices
- at
- (-4, 0)
- (4, 0)
-
- (- \(\sqrt{7}\), 0)
- (\(\sqrt{7}\), 0)
Major and Minor Axes
In an ellipse, the major axis is the longer diameter, while the minor axis is the shorter one. These two axes define the proportions and the elongation level of the ellipse.
The length of the major axis in this ellipse is 8. As it is aligned with the x-axis, the distance from the center to each end of major axis (the semi-major axis) is
The length of the major axis in this ellipse is 8. As it is aligned with the x-axis, the distance from the center to each end of major axis (the semi-major axis) is
- 4 units (because 8/2 = 4)
- 3 units (since 6/2 = 3) away from the origin.
Center at Origin
When an ellipse is centered at the origin, the coordinates of its center are at
For an ellipse aligned along the axes, the general equation with a center at the origin is given by:\[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \]where
- (0,0)
For an ellipse aligned along the axes, the general equation with a center at the origin is given by:\[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \]where
-
- \(a\) is the semi-major axis
- \(b\) is the semi-minor axis
Other exercises in this chapter
Problem 32
Make a sketch of the region and its bounding curves. Find the area of the region. The region inside the right lobe of \(r=\sqrt{\cos 2 \theta}\) and inside the
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Make a sketch of the region and its bounding curves. Find the area of the region. The region inside one leaf of the rose \(r=\cos 5 \theta\)
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Find an equation of the following ellipses, assuming the center is at the origin. Sketch a graph labeling the vertices and foci. An ellipse with vertices (±6,0)
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