Problem 33
Question
Find a polar equation that has the same graph as the equation in \(x\) and \(y\). $$x^{2}+(y+3)^{2}=9$$
Step-by-Step Solution
Verified Answer
The polar equation is \( r = 6 \sin(\theta) + 3 \).
1Step 1: Convert Cartesian Equation to Standard Circle Form
The given equation is \( x^2 + (y+3)^2 = 9 \), which describes a circle in the Cartesian coordinate system. This equation can be rewritten as a standard circle equation: \((x - 0)^2 + (y - (-3))^2 = 3^2\). Thus, it represents a circle with center at \((0, -3)\) and radius \(3\).
2Step 2: Express Circle Center in Polar Coordinates
The center of the circle in Cartesian coordinates, \((0, -3)\), can be converted to polar coordinates. In polar form, the center \((0, -3)\) has radial distance \(r_c = 3\) and angle \( \theta_c = \frac{3\pi}{2} \).
3Step 3: Use Polar Circle Equation Formula
The polar equation of a circle with a center at \((r_c, \theta_c)\) and radius \(R\) is given by the formula: \( r = 2R \cos(\theta - \theta_c) + r_c \). Substituting the values \(R = 3\), \(r_c = 3\), and \(\theta_c = \frac{3\pi}{2}\), we have:\[r = 2 \times 3 \times \cos(\theta - \frac{3\pi}{2}) + 3.\]
4Step 4: Simplify the Polar Equation
Compute \(\cos(\theta - \frac{3\pi}{2})\). Using the identity \(\cos(a - b) = \sin(b)\), we find \(\cos(\theta - \frac{3\pi}{2}) = \sin(\theta)\). Thus, the polar equation simplifies to: \[r = 6 \sin(\theta) + 3.\]
Key Concepts
Cartesian CoordinatesPolar CoordinatesCircle EquationsCoordinate Transformation
Cartesian Coordinates
Cartesian coordinates are a system that uses two numerical values to determine a position on a plane. These two values are typically represented as
- x: the horizontal position on the plane
- y: the vertical position on the plane
Polar Coordinates
Polar coordinates offer an alternative means to describe locations on a plane.Instead of using horizontal and vertical distances, the polar coordinate system employs:
In the context of a circle, this characteristic makes polar coordinates a suitable choice to depict curves efficiently, adapting perfectly to the circular symmetry. Simplifying trigonometric calculations further makes polar coordinates popular for scenarios involving rotational movement and cycles. For instance, any adjustment in the angle \(\theta\) allows us to easily rotate the point around the origin.
- r: the radial distance from the origin
- \(\theta\): the angle from the positive x-axis to the line connecting the origin to the point
In the context of a circle, this characteristic makes polar coordinates a suitable choice to depict curves efficiently, adapting perfectly to the circular symmetry. Simplifying trigonometric calculations further makes polar coordinates popular for scenarios involving rotational movement and cycles. For instance, any adjustment in the angle \(\theta\) allows us to easily rotate the point around the origin.
Circle Equations
Circle equations can be represented in either Cartesian or polar form, each offering a distinct perspective to understanding circles' geometry.
The standard Cartesian equation for a circle is \[(x - h)^2 + (y - k)^2 = r^2\]where \((h, k)\) is the circle's center and \(r\) its radius. This form effectively depicts the round shape using the distance formula.
In contrast, the polar equation for a circle offers a different visualization: \[r = 2R \cos(\theta - \theta_c) + r_c\] where
The standard Cartesian equation for a circle is \[(x - h)^2 + (y - k)^2 = r^2\]where \((h, k)\) is the circle's center and \(r\) its radius. This form effectively depicts the round shape using the distance formula.
In contrast, the polar equation for a circle offers a different visualization: \[r = 2R \cos(\theta - \theta_c) + r_c\] where
- \(R\) is the circle's radius,
- \(\theta_c\) is the angle corresponding to the center, and
- \(r_c\) is the radial distance to the center from the origin
Coordinate Transformation
Coordinate transformation is the process that allows conversion between different coordinate systems, such as from Cartesian to polar coordinates and vice versa. This transformation is essential because each system has specific uses or advantages depending on the problem context. For instance:
- Cartesian coordinates are often preferred for linear movement analysis
- Polar coordinates often excel in rotational or radial symmetry contexts
- Converting from Cartesian to Polar: \(r = \sqrt{x^2 + y^2}\) and \(\theta = \tan^{-1}(y/x)\)
- Converting from Polar to Cartesian: \(x = r \cos(\theta)\) and \(y = r \sin(\theta)\)
Other exercises in this chapter
Problem 33
Find a polar equation of the parabola with focus at the pole and the given vertex. $$V\left(4, \frac{\pi}{2}\right)$$
View solution Problem 33
Find an equation for the hyperbola that has its center at the origin and satisfies the given conditions. \(x\) -intercepts \(\pm 5, \quad\) asymptotes \(y=\pm 2
View solution Problem 33
Exer \(19-36:\) Find an equation for the ellipse that has its center at the origin and satisfies the given conditions. \(x\) -intercepts \(\pm 2\) \(y\) -interc
View solution Problem 33
Find an equation of the parabola that satisfies the given conditions. Vertex at the origin, symmetric with respect to the \(y\) -axis, and passing through the p
View solution