Problem 33
Question
Find a parametrization for the circle \((x-2)^{2}+y^{2}=1\) starting at \((1,0)\) and moving clockwise once around the circle, using the central angle \(\theta\) in the accompanying figure as the parameter.
Step-by-Step Solution
Verified Answer
Parametrize with \(x = 2 + \cos(\pi + \theta), y = -\sin(\pi + \theta), \theta \in [0, 2\pi]\).
1Step 1: Identify Circle Equation Parameters
The given circle equation is \[(x-2)^2 + y^2 = 1.\]This implies that the circle has its center at \((2, 0)\) and radius \(1\).
2Step 2: Determine Standard Parametric Equations
A standard parametrization for a circle with center \((h, k)\) and radius \(r\) is \[x = h + r \cos(\theta) \y = k + r \sin(\theta).\]In our case, \(h=2\), \(k=0\), and \(r=1\). Substituting these into the standard formula, we get:\[x = 2 + \cos(\theta) \y = \sin(\theta).\]
3Step 3: Adjust for Clockwise Motion
Since the problem specifies a clockwise parameterization, we need to reverse the standard trigonometric functions:\[x = 2 + \cos(\theta) \y = - \sin(\theta).\]This change makes the circle traverse clockwise as \(\theta\) increases.
4Step 4: Check Parameterization Start Point
For \(\theta = 0\), the point is:\[x = 2 + \cos(0) = 3 \y = - \sin(0) = 0.\]We must find where \((1, 0)\) lies. Adjusting \(\theta\) so that \(x = 1\) results in\[\cos(\theta) = 1 - 2 = -1.\]This happens at \(\theta = \pi\), so the parametrization is \[x = 2 + \cos(\pi + \theta), \y = - \sin(\pi + \theta).\]
5Step 5: Verify the Solution and Parameter Range
Calculating for \(\theta = \pi\) in parameterization,\[x = 2 + \cos(2\pi) = 1 \y = - \sin(2\pi) = 0.\]Hence, it starts at \((1, 0)\). The parameter \(\theta\) should range from \(0\) to \(2\pi\) to complete one full clockwise rotation around the circle.
Key Concepts
Clockwise MotionCircle EquationTrigonometric Functions
Clockwise Motion
In the realm of mathematics, understanding the direction of motion around a circle is important. Typically, parametric equations of a circle use trigonometric functions that describe a counterclockwise motion.
However, when the task involves moving clockwise, we must adjust these functions. In standard form, the parameterization for counterclockwise motion involves
By reversing the sign, you effectively move in the opposite direction around the circle. Thus, the clockwise parameterization becomes:
However, when the task involves moving clockwise, we must adjust these functions. In standard form, the parameterization for counterclockwise motion involves
- \(x = h + r \cos(\theta)\)
- \(y = k + r \sin(\theta)\)
By reversing the sign, you effectively move in the opposite direction around the circle. Thus, the clockwise parameterization becomes:
- \(x = h + r \cos(\theta)\)
- \(y = k - r \sin(\theta)\)
Circle Equation
A circle equation in its standard form is \((x-h)^2 + (y-k)^2 = r^2\), where:
Knowing this allows us to find parametric equations that represent the same circle, enabling us to map specific points or directions with precise calculations.
- \((h, k)\) is the center of the circle
- \(r\) represents the radius of the circle
Knowing this allows us to find parametric equations that represent the same circle, enabling us to map specific points or directions with precise calculations.
Trigonometric Functions
Trigonometric functions are key to translating angles into coordinates along a circle.
In parametrizing a circle, we predominantly use cosine and sine functions:
Adjusting the sign of sine to negative, as done in clockwise motion, leverages these functions effectively to reverse travel direction.
In parametrizing a circle, we predominantly use cosine and sine functions:
- \(\cos(\theta)\) represents horizontal displacement
- \(\sin(\theta)\) represents vertical displacement
- \(x = h + r \cos(\theta)\)
- \(y = k + r \sin(\theta)\)
Adjusting the sign of sine to negative, as done in clockwise motion, leverages these functions effectively to reverse travel direction.
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