Problem 33
Question
Exercises \(33-38:\) Write a formula for a linear function f whose graph satisfies the conditions. $$ \text { Slope }-\frac{3}{4}, y \text { -intercept } \frac{1}{3} $$
Step-by-Step Solution
Verified Answer
The formula is \( f(x) = -\frac{3}{4}x + \frac{1}{3} \).
1Step 1: Understand the Linear Function Formula
A linear function can be represented in the form \( f(x) = mx + b \), where \( m \) is the slope, and \( b \) is the \( y \)-intercept. We need to identify these values from the given conditions.
2Step 2: Substitute the Given Slope
Substitute the slope \( m = -\frac{3}{4} \) into the linear function formula: \( f(x) = -\frac{3}{4}x + b \).
3Step 3: Substitute the Given Y-intercept
Substitute the \( y \)-intercept \( b = \frac{1}{3} \) into the equation from Step 2: \( f(x) = -\frac{3}{4}x + \frac{1}{3} \).
4Step 4: Write the Final Formula
The formula for the linear function that satisfies the given conditions is \( f(x) = -\frac{3}{4}x + \frac{1}{3} \).
Key Concepts
Slope of a LineY-interceptLinear Equations
Slope of a Line
The slope of a line is a crucial concept within linear functions and geometry. The slope, often represented as \( m \), essentially measures the steepness or incline of a line. You can think of it as the amount of vertical change for every unit of horizontal change. Mathematically, the slope is calculated by taking the difference in \( y \)-values and dividing it by the difference in \( x \)-values between two points on the line:
\[ m = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1} \]
In our example, the given slope is \(-\frac{3}{4}\). This means for every 4 units you move horizontally to the right, the line moves 3 units vertically down, indicating a decreasing or negative slope. The slope direction determines whether the line moves upward or downward as it progresses from left to right on the graph. A positive slope means the line rises, while a negative slope, like \(-\frac{3}{4}\), means it falls.
\[ m = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1} \]
In our example, the given slope is \(-\frac{3}{4}\). This means for every 4 units you move horizontally to the right, the line moves 3 units vertically down, indicating a decreasing or negative slope. The slope direction determines whether the line moves upward or downward as it progresses from left to right on the graph. A positive slope means the line rises, while a negative slope, like \(-\frac{3}{4}\), means it falls.
- Positive slope: Line increases from left to right
- Negative slope: Line decreases from left to right
- Zero slope: Horizontal line
- Undefined slope: Vertical line
Y-intercept
The \( y \)-intercept is another fundamental concept in understanding linear functions. Represented by \( b \) in the linear equation \( f(x) = mx + b \), the \( y \)-intercept is the point where the line crosses the \( y \)-axis. When graphing, it provides the starting point on the \( y \) axis, from which you apply the slope to determine the direction and angle of the line.
In the context of this problem, the \( y \)-intercept is \( \frac{1}{3} \). This means that when \( x = 0 \), \( f(x) \), or \( y \), equals \( \frac{1}{3} \). If you imagine drawing the line on a graph, you'd start by plotting the point \( (0, \frac{1}{3}) \) and from this point, you follow the slope to draw the rest of the line. The beauty of the \( y \)-intercept is how it provides clarity in positioning where the line begins on the vertical axis, distinct from the slope's guidance in line direction.
In the context of this problem, the \( y \)-intercept is \( \frac{1}{3} \). This means that when \( x = 0 \), \( f(x) \), or \( y \), equals \( \frac{1}{3} \). If you imagine drawing the line on a graph, you'd start by plotting the point \( (0, \frac{1}{3}) \) and from this point, you follow the slope to draw the rest of the line. The beauty of the \( y \)-intercept is how it provides clarity in positioning where the line begins on the vertical axis, distinct from the slope's guidance in line direction.
- \( y \)-intercept: The \( y \)-value where \( x \) is 0
- Affects the line's vertical position on a graph
Linear Equations
Linear equations are foundational to understanding mathematical relationships and represent relationships between variables. The standard form of a linear function is \( f(x) = mx + b \), where \( m \) and \( b \) hold specific roles:
- \( m \) represents the slope
- \( b \) represents the \( y \)-intercept
Linear equations model straight-line relationships where the value of \( y \) changes at a consistent rate with respect to \( x \). This consistency is visually represented by straight lines when plotted on a Cartesian plane.
For the equation \( f(x) = -\frac{3}{4}x + \frac{1}{3} \) derived from the exercise:
- \( m \) represents the slope
- \( b \) represents the \( y \)-intercept
Linear equations model straight-line relationships where the value of \( y \) changes at a consistent rate with respect to \( x \). This consistency is visually represented by straight lines when plotted on a Cartesian plane.
For the equation \( f(x) = -\frac{3}{4}x + \frac{1}{3} \) derived from the exercise:
- The slope \(-\frac{3}{4}\) dictates a downward angle
- The \( y \)-intercept \(\frac{1}{3}\) provides the initial position on the \( y \) axis
Other exercises in this chapter
Problem 33
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Solve the equation and check your answer. $$ \frac{3 x-1}{5}-2=\frac{2-x}{3} $$
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