Problem 33
Question
Exer. 33-34: (a) Find the radian and degree measures of the central angle \(\boldsymbol{\theta}\) subtended by the given are of length \(s\) on a circle of radius \(r .\) (b) Find the area of the sector determined by \(\theta\) $$s=7 \mathrm{cm}, \quad r=4 \mathrm{cm}$$
Step-by-Step Solution
Verified Answer
(a) \(\theta = \frac{7}{4}\) radians, \(100.53^\circ\); (b) Area = 14 cm².
1Step 1: Understand the Relationship Between Arc Length, Radius, and Radians
To find the radian measure of the central angle \(\theta\), recall the formula for arc length:\(s = r \theta\). Here, \(s\) is the arc length, \(r\) is the radius, and \(\theta\) is given in radians.
2Step 2: Calculate the Radian Measure of \(\theta\)
Using the formula \(s = r \theta\), plug in the given values: \(7 = 4 \theta\). Solve for \(\theta\): \(\theta = \frac{7}{4}\) radians.
3Step 3: Convert Radian Measure to Degrees
To convert radians to degrees, use the conversion factor \(\frac{180}{\pi}\). So, \(\theta\) in degrees is \(\frac{7}{4} \times \frac{180}{\pi} \approx 100.53^\circ\).
4Step 4: Use \(\theta\) to Determine the Area of the Sector
The area \(A\) of the sector is given by the formula \(A = \frac{1}{2} r^2 \theta\), where \(\theta\) is in radians. Substitute the known values: \(A = \frac{1}{2} \times 4^2 \times \frac{7}{4}\).
5Step 5: Calculate the Area of the Sector
Perform the arithmetic: \(A = \frac{1}{2} \times 16 \times \frac{7}{4} = \frac{28}{2} = 14\). So, the area of the sector is 14 square centimeters.
Key Concepts
Radian MeasureDegree ConversionArc LengthSector Area
Radian Measure
When dealing with circles, the concept of a radian is fundamental. It is an alternate way to measure angles instead of the more familiar degree measurement. One radian is defined as the angle subtended by an arc that has a length equal to the circle's radius. To find the radian measure of an angle, you use the formula for arc length: \(s = r\theta\). Here, \(s\) is the arc length, \(r\) is the radius of the circle, and \(\theta\) is the angle in radians. In the given problem, with an arc length of 7 cm and a radius of 4 cm, you rearrange the formula to solve for \(\theta\):
- \(\theta = \frac{s}{r} = \frac{7}{4}\) radians.
Degree Conversion
Though radians are essential in mathematics, degrees are often more intuitive since they are part of everyday language. Degrees can be converted from radians using the fixed ratio \(\frac{180}{\pi}\), because one full circle is \(2\pi\) radians or 360 degrees. The conversion formula is:\[\text{Degrees} = \text{Radians} \times \frac{180}{\pi}\]Using our example where \(\theta = \frac{7}{4}\) radians, the degree measure is:
- \(\frac{7}{4} \times \frac{180}{\pi} \approx 100.53^\circ\).
Arc Length
Arc length is a segment of the circumference of a circle. It's directly related to the radian measure of the central angle and the radius of the circle. The arc length formula \(s = r\theta\) helps link both of these elements. Consider this – when the angle \(\theta\) is measured in radians, the arc length \(s\) provides a sense of how much of the circle's outline is covered by the angle. In our example:
- The arc length was given as 7 cm.
- The radius was 4 cm.
Sector Area
The concept of sector area comes into play when you want to find out the space enclosed by two radii and the arc between them. The formula for calculating the area of a sector is:\[A = \frac{1}{2} r^2 \theta\]where \(A\) is the area, \(r\) is the radius, and \(\theta\) is the angle in radians. To determine the area of the sector in our problem:
- We use \(\theta = \frac{7}{4}\) radians and \(r = 4\) cm.
- The calculation is \(A = \frac{1}{2} \times 4^2 \times \frac{7}{4} = 14\) square centimeters.
Other exercises in this chapter
Problem 32
Find the amplitude, the period, and the phase shift and sketch the graph of the equation. \(y=4 \sin \left(\frac{1}{3} x-\frac{\pi}{3}\right)\)
View solution Problem 32
Approximate to four decimal places, when appropriate. (a) \(\sin (-0.11)\) (b) \(\sec \frac{31}{27}\) (c) \(\cos (-8.54)\) (d) \(\tan (3 \pi / 7)\)
View solution Problem 33
Find the amplitude, the period, and the phase shift and sketch the graph of the equation. \(y=4 \sin \left(\frac{1}{3} x-\frac{\pi}{3}\right)\)
View solution Problem 33
Approximate to four decimal places, when appropriate. (a) \(\sin 30^{\circ}\) (b) \(\sin 30\) (c) \(\cos \pi^{\circ}\) (d) \(\cos \pi\)
View solution