Problem 33
Question
Evaluate the expression without using a calculator.\(\log _{7} 7\)
Step-by-Step Solution
Verified Answer
The evaluated expression \(\log _{7} 7\) is 1.
1Step 1: Understand the call of the question
The key to solving this exercise is understanding that the expression \(\log_{7}7\) represents the power to which the base number (7) must be raised to produce the number given within the log (also 7).
2Step 2: Apply Logarithmic Laws
When we apply the laws of logarithms it indicates that any value of 'a' where \(a > 0\), the result of \(\log_{a}a\) is equal to 1. Because in this case, you're trying to find the power to which the base (7) must be raised to result in the number 7 itself.
3Step 3: Conclude your answer
Therefore, \(\log_{7}7\) equals 1. This is because 7 to the power of 1 gives you 7, satisfying the conditions of a logarithmic expression.
Key Concepts
Logarithmic LawsLogarithmic ExpressionsExponents
Logarithmic Laws
Logarithmic laws are essential rules that simplify the manipulation and evaluation of logarithmic expressions. These laws are much like the laws of exponents, helping us understand and solve problems involving logarithms easily.
The most crucial law involved in this exercise is the identity law. The identity law states that for any base "a" where "a" is greater than zero, the logarithm of "a" to its own base is always 1. Mathematically, this is expressed as \(\log_{a}a = 1\).
The most crucial law involved in this exercise is the identity law. The identity law states that for any base "a" where "a" is greater than zero, the logarithm of "a" to its own base is always 1. Mathematically, this is expressed as \(\log_{a}a = 1\).
- The reason behind this is that the logarithm asks the question: "To what power must we raise 'a' to obtain 'a'?" The answer is clearly 1, since any number raised to the first power is itself.
Logarithmic Expressions
A logarithmic expression is a mathematical expression involving a logarithm. It's a way of expressing how many times you need to multiply a base number to get another number. In notation, it's written as \(\log_{a}b\), where "a" is the base and "b" is the number you want to achieve through repeated multiplication of "a".
This helps in decoding the mathematical implications of what the logarithm is asking. The expression \(\log_{7}7\) illustrates this clearly, as it asks how many times we must multiply 7 by itself to get 7, which, unsurprisingly, is once.
- The expression \(\log_{a}b\) essentially asks: "What exponent do we need for base 'a' to get 'b'?"
- So, if \(b = a^x\), then \(\log_{a}b = x\).
This helps in decoding the mathematical implications of what the logarithm is asking. The expression \(\log_{7}7\) illustrates this clearly, as it asks how many times we must multiply 7 by itself to get 7, which, unsurprisingly, is once.
Exponents
Exponents are a way to express repeated multiplication of a number by itself. If we have a number "a" raised to the power of "x", it means we're multiplying "a" by itself "x" times. This concept is fundamental in understanding both exponents and logarithms.
This interconnectedness is key to grasp, making it easier to transition between and solve problems involving both exponents and logarithms.
- For instance, \(a^1 = a\), illustrating that any number raised to the power of 1 is the number itself.
- This principle is pivotal to understanding the identity law of logarithms, such as \(\log_{a}a\).
This interconnectedness is key to grasp, making it easier to transition between and solve problems involving both exponents and logarithms.
Other exercises in this chapter
Problem 33
Solve the exponential equation algebraically. Approximate the result to three decimal places.\(3^{x-1}=28\)
View solution Problem 33
Evaluate the logarithm. Round your result to three decimal places.\(\log _{1 / 4} 10\)
View solution Problem 33
Sketch the graph of the function.\(f(x)=e^{2 x}\)
View solution Problem 34
Solve the exponential equation algebraically. Approximate the result to three decimal places.\(2^{x-3}=31\)
View solution