Problem 33
Question
Evaluate \(_{n} P_{r}\) using the formula from this section. $$_{8} P_{3}$$
Step-by-Step Solution
Verified Answer
Therefore, \( _{8} P_{3} = 336 \).
1Step 1: Identify n and r
We are to solve for \( _{8} P_{3} \), meaning \( n = 8 \) and \( r = 3 \).
2Step 2: Substitute n and r into the formula
Substitute \( n \) and \( r \) into the permutation formula. It becomes \( \frac{8!}{(8 - 3)!} \). Now simplify the equation.
3Step 3: Simplify the equation
Simplify the equation to \( \frac{8!}{5!} \). Calculating the factorials gives \( \frac{40320}{120} \).
4Step 4: Perform the division
Dividing 40320 by 120 gives 336.
Key Concepts
FactorialsCombinatoricsPermutation Formula
Factorials
Factorials are a fundamental concept in mathematics that demonstrate how to calculate the product of all positive integers up to a given number. This is denoted by an exclamation point. For example, the factorial of 5, written as 5!, means 5 multiplied by every positive whole number below it. Hence, 5! = 5 × 4 × 3 × 2 × 1 = 120.
Understanding factorials is crucial for solving permutations and combinations since these mathematical tools rely heavily on the repetitive product of sequential numbers.
Note also that 0! is defined as 1. This might seem strange, but it's used to maintain the mathematical consistency of arrangements and calculations.
Understanding factorials is crucial for solving permutations and combinations since these mathematical tools rely heavily on the repetitive product of sequential numbers.
Note also that 0! is defined as 1. This might seem strange, but it's used to maintain the mathematical consistency of arrangements and calculations.
Combinatorics
Combinatorics is a branch of mathematics focused on counting, arranging, and analyzing sets of elements. It's particularly useful for determining the number of ways elements can be selected or organized.
For a practical example, consider trying to find out how many ways you can arrange a set of books or select items for a committee.
Combinatorics helps solve such problems by utilizing concepts like permutations, combinations, and the pigeonhole principle.
For a practical example, consider trying to find out how many ways you can arrange a set of books or select items for a committee.
Combinatorics helps solve such problems by utilizing concepts like permutations, combinations, and the pigeonhole principle.
- Permutations: Arranging items where order matters.
- Combinations: Selecting items where order does not matter.
- Pigeonhole Principle: Proving the inevitability of certain arrangements.
Permutation Formula
The permutation formula is a mathematical expression used to determine the number of arrangements of a subset of items. This formula is applicable when the order of arrangement is important. The formula is denoted by \( _{n} P_{r} = \frac{n!}{(n - r)!} \), where:
\[ _{8} P_{3} = \frac{8!}{(8 - 3)!} = \frac{8!}{5!} \]
After calculating the factorials, this reduces to \( \frac{40320}{120} = 336 \).
This result shows there are 336 ways to arrange a group of 3 out of 8 items, where the order matters.
- \( n \) is the total number of items.
- \( r \) is the number of items to arrange.
\[ _{8} P_{3} = \frac{8!}{(8 - 3)!} = \frac{8!}{5!} \]
After calculating the factorials, this reduces to \( \frac{40320}{120} = 336 \).
This result shows there are 336 ways to arrange a group of 3 out of 8 items, where the order matters.
Other exercises in this chapter
Problem 33
Find the indicated term of the sequence. $$\begin{aligned} &a_{n}=\frac{n^{2}}{n^{2}+1}\\\ &a_{10}= \end{aligned}$$
View solution Problem 33
Write the first five terms of the arithmetic sequence. Use the table feature of a graphing utility to verify your results. $$a_{1}=-2.6, d=0.2$$
View solution Problem 33
The complement of an event \(A\) is the collection of all outcomes in the sample space that are not in \(A\). If the probability of \(A\) is \(P(A),\) then the
View solution Problem 33
Finding a Term of a Geometric Sequence Find the indicated term of the geometric sequence (a) using the table feature of a graphing utility and (b) algebraically
View solution