Problem 33

Question

Enthalpy Changes Nitrogen monoxide, a gas recently found to be involved in a wide range of biological processes, reacts with oxygen to give brown \(\mathrm{NO}_{2}\) gas. $$ \begin{aligned} 2 \mathrm{NO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \rightarrow & 2 \mathrm{NO}_{2}(\mathrm{g}) \\ \Delta_{r} H^{\circ} &=-114.1 \mathrm{kJ} / \mathrm{mol}-\mathrm{pxn} \end{aligned} $$ Is this reaction endothermic or exothermic? What is the enthalpy change if \(1.25 \mathrm{g}\) of \(\mathrm{NO}\) is converted completely to \(\mathrm{NO}_{2} ?\)

Step-by-Step Solution

Verified
Answer
The reaction is exothermic. The enthalpy change for 1.25 g of NO is approximately -2.378 kJ.
1Step 1: Determine Reaction Type
First, examine the given standard enthalpy change of the reaction, \(\Delta_r H^{\circ} = -114.1\, \text{kJ/mol-pxn}\). A negative sign indicates that the reaction releases energy, meaning it is an exothermic reaction.
2Step 2: Find Molar Mass of NO
Calculate the molar mass of nitrogen monoxide (NO). Nitrogen (N) has an atomic mass of approximately 14.01 amu, and oxygen (O) has an atomic mass of about 16.00 amu. Therefore, the molar mass of NO is \(14.01 + 16.00 = 30.01\, \text{g/mol}\).
3Step 3: Calculate Moles of NO in 1.25 g
To find the number of moles of NO in 1.25 g, use the formula: \(\text{moles} = \text{mass} / \text{molar mass}\). Thus, \[ \text{moles of NO} = \frac{1.25\, \text{g}}{30.01\, \text{g/mol}} \approx 0.04165\, \text{mol}. \]
4Step 4: Compute Enthalpy Change for 1.25 g of NO
The reaction given is for 2 moles of NO leading to \(\Delta_r H^{\circ} = -114.1\, \text{kJ/mol-pxn}\). For 0.04165 moles of NO, since the reaction releases \(-114.1\, \text{kJ}\) for every 2 moles, calculate the enthalpy change as: \[ \Delta H = 0.04165\, \text{mol} \times \frac{-114.1\, \text{kJ/mol}}{2\, \text{mol}} \approx -2.378\, \text{kJ}. \]

Key Concepts

Exothermic ReactionsMolar Mass CalculationReaction Enthalpy CalculationNitrogen Monoxide Reactions
Exothermic Reactions
An exothermic reaction is a chemical process that releases energy, typically in the form of heat, to its surroundings. When you are dealing with such reactions, you often notice a temperature increase in the surrounding environment. This is because energy is leaving the reaction.
Some key characteristics of exothermic reactions include:
  • They have a negative enthalpy change (\( \Delta H < 0 \)), meaning that the energy of the products is less than that of the reactants.
  • They often occur spontaneously because releasing energy is a favorable process.
  • Combustion, for instance, is a common example of an exothermic reaction.
In the case of the reaction between nitrogen monoxide and oxygen forming nitrogen dioxide, the reaction is exothermic. This deduction is supported by the negative enthalpy change (\(\Delta_{r} H^{\circ} = -114.1 \text{kJ/mol-pxn}\)), indicating the release of energy.
Molar Mass Calculation
Calculating molar mass is a foundational skill in chemistry, essential for converting between grams and moles. This involves summing the atomic masses of all the atoms in a molecular formula.
For nitrogen monoxide (NO), the calculation proceeds as follows:
  • Nitrogen (N) has an atomic mass of about 14.01 amu.
  • Oxygen (O) has an atomic mass of about 16.00 amu.
  • Thus, the molar mass of NO is the sum of these two values: \(14.01 + 16.00 = 30.01 \text{g/mol}\).
Understanding molar mass is crucial when performing unit conversion in chemical reactions, such as determining how many moles a given mass corresponds to. This step is critical when calculating reaction yields or enthalpy changes for specific amounts of reactants.
Reaction Enthalpy Calculation
The enthalpy change of a reaction provides insight into whether the process absorbs or releases energy. Calculating the enthalpy change for specific amounts of reactants is a common task in thermochemistry.
In this scenario, calculating the enthalpy change involves:
  • Knowing the reaction's enthalpy change per mole, given as \(\Delta_{r} H^{\circ} = -114.1 \text{kJ/mol-pxn}\).
  • Determining the molar quantity of a reactant, here 1.25 g of NO is used.
  • Calculating the number of moles using the formula: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}}\).
  • The moles of NO calculated are approximately 0.04165 mol.
    Since the enthalpy change applies to 2 moles, we divide the total enthalpy release by this factor to find: \(\Delta H = 0.04165 \times \frac{-114.1}{2} \approx -2.378 \text{kJ}\).
This calculation shows the specific energy change when 1.25 g of NO reacts under standard conditions.
Nitrogen Monoxide Reactions
Nitrogen monoxide (NO) is a colorless gas and plays essential roles in various chemical and biological processes. It is notably reactive with oxygen, leading to the formation of nitrogen dioxide (NO\(_2\)). The reaction can be described as follows:\[ 2 \text{NO}(g) + \text{O}_2(g) \rightarrow 2 \text{NO}_2(g)\]
Nitrogen monoxide's environmental and health impacts include:
  • Contributing to air pollution and forming smog when reacted with other atmospheric components.
  • Playing a role in biological systems, acting as a signaling molecule in the body, for example, in vasodilation.
  • Its reaction with oxygen is exothermic, releasing substantial energy as described by the reaction's enthalpy change.
Understanding the behavior and reactions of nitrogen monoxide is crucial in both chemistry and environmental sciences due to its widespread implications.