Problem 33
Question
Determine whether the integral is convergent or divergent. Evaluate all convergent integrals. Be efficient. If \(\lim _{x \rightarrow \infty} \neq 0\), then \(\int_{a}^{\infty} f(x) d x\) is divergent. \(\int_{0}^{\pi} \tan x d x\)
Step-by-Step Solution
Verified Answer
The integral \(\int_{0}^{\pi} \tan x d x\) is divergent.
1Step 1: Evaluate the limit of the function
First, we evaluate the limit of the function \(\tan x\) as \(x \rightarrow \pi\) from the left, denoted as \(\lim_{x \rightarrow \pi^-} \tan x\). This limit translations into evaluating the value of tangent function slightly before \(\pi\), where it is undefined.
2Step 2: Determine if the integral diverges or converges
As tangent approaches \(\pi\) from the left, the function goes to negative infinity. Since the limit is not zero, \(\lim_{x \rightarrow \pi^-} \tan x = -\infty\), we can say using the given criteria that the integral \(\int_{0}^{\pi} \tan x d x\) diverges.
Key Concepts
Improper IntegralsConvergence and DivergenceTangent Function
Improper Integrals
Improper integrals are a special type of integral that deal with unbounded intervals or unbounded functions. These integrals need extra attention because they involve limits to deal with their infinite aspects. For instance, an integral might have limits going towards infinity or a function that becomes infinite at certain points within the interval. Instead of using usual integration techniques, we must carefully compute them by taking limits.
Consider the integral \[ \int_{a}^{b} f(x)\, dx \] If the limit is either infinite or if there is a point within \[a, b\] where \(f(x)\) approaches infinity, the integral becomes improper.
Improper integrals can still be handled meaningfully by determining if they converge or diverge. They converge if the area under the curve is finite, otherwise, they diverge. This involves evaluating the limit as the function or bounds approach infinity.
Consider the integral \[ \int_{a}^{b} f(x)\, dx \] If the limit is either infinite or if there is a point within \[a, b\] where \(f(x)\) approaches infinity, the integral becomes improper.
Improper integrals can still be handled meaningfully by determining if they converge or diverge. They converge if the area under the curve is finite, otherwise, they diverge. This involves evaluating the limit as the function or bounds approach infinity.
Convergence and Divergence
When dealing with improper integrals, two key terms, convergence and divergence, come into play. They essentially describe the behavior of the integral as it approaches potentially problematic points.
Convergence means that as we calculate the integral and resolve the infinity issues, the result is a finite number. This indicates that overall, the area under the curve represented by the function is limited, even when stretching towards infinity.
Convergence means that as we calculate the integral and resolve the infinity issues, the result is a finite number. This indicates that overall, the area under the curve represented by the function is limited, even when stretching towards infinity.
- A convergent improper integral comes to a specific number.
- Convergence implies manageable behavior over infinite stretches.
- A divergent improper integral does not yield a finite result.
- Divergence means unmanageable or limitless behavior over infinite stretches.
Tangent Function
The tangent function, \( \tan x \), is one of the fundamental trigonometric functions. It is defined as the ratio of the sine function to the cosine function:
\[ \tan x = \frac{\sin x}{\cos x} \]The properties of the tangent function can lead to interesting behaviors that play an important role in calculus.
\[ \tan x = \frac{\sin x}{\cos x} \]The properties of the tangent function can lead to interesting behaviors that play an important role in calculus.
- The function has a periodic nature with a period of \(\pi\).
- Tangent is undefined when \(\cos x = 0\). This happens at odd multiples of \(\frac{\pi}{2}\).
- The function approaches infinity as \(x\) approaches these undefined points from one side, and negative infinity from the other side, creating vertical asymptotes.
Other exercises in this chapter
Problem 32
Evaluate the integrals. Not all require a trigonometric substitution. Choose the simplest method of integration. \(\int \frac{x^{3}}{\sqrt{4+x^{2}}} d x\)
View solution Problem 33
Show that \(\int(\ln x)^{n} d x=x(\ln x)^{n}-n \int(\ln x)^{n-1} d x\).
View solution Problem 33
Evaluate the integrals. Not all require a trigonometric substitution. Choose the simplest method of integration. \(\int \frac{1}{\sqrt{9+x^{2}}} d x\)
View solution Problem 34
Show that \(\int x^{n} e^{x} d x=x^{n} e^{x}-n \int x^{n-1} e^{x} d x\).
View solution