Problem 33
Question
Determine whether each equation defines \(y\) to be a function of \(x .\) If it does not, find two ordered pairs where more than one value of \(y\) corresponds to a single value of \(x .\) $$ y=\frac{1}{x} $$
Step-by-Step Solution
Verified Answer
Yes, \( y = \frac{1}{x} \) defines \( y \) as a function of \( x \) for \( x \neq 0 \).
1Step 1: Identify the Equation Type
The given equation is \( y = \frac{1}{x} \), which is a rational function where \( y \) is expressed explicitly in terms of \( x \).
2Step 2: Understand What Defines a Function
A relation is a function if each input \( x \) has exactly one output \( y \). We must check if, for every \( x \), there is only one corresponding \( y \).
3Step 3: Check for Multiple Outputs
In this equation, for a given non-zero value of \( x \), the output \( y = \frac{1}{x} \) is uniquely determined to be one specific value. Since the equation simplifies directly to a single \( y \) for every non-zero \( x \), there are not instances of multiple outputs for the same input.
4Step 4: Consider Restrictions on the Domain
For \( x = 0 \), the equation is undefined because division by zero is not possible. However, this does not affect the determination, as the function can be restricted to \( x eq 0 \).
5Step 5: Conclude Function Status
Since for all allowed inputs (\( x eq 0 \)), \( y \) is uniquely determined. Therefore, \( y = \frac{1}{x} \) does define \( y \) as a function of \( x \).
Key Concepts
Rational FunctionsDomain RestrictionsFunction Definition
Rational Functions
Rational functions play an important role in algebra and calculus. A rational function is essentially a ratio of two polynomials. In simpler terms, it's a fraction where the numerator and the denominator are polynomials. For instance, the function \( y = \frac{1}{x} \) is a basic example of a rational function with a numerator of 1 and a denominator of \( x \). The behavior of these functions can be quite interesting due to the properties of fractions.
- They are defined by polynomials in the numerator and denominator.
- They can have vertical asymptotes, which occur where the denominator is zero.
- The domain of a rational function excludes values that make the denominator zero.
Domain Restrictions
In mathematics, the domain of a function is the set of all possible input values (typically \( x \)) that the function can accept. Domain restrictions occur when certain values of \( x \) result in undefined or undesirable outputs, such as division by zero or square roots of negative numbers.
For the function \( y = \frac{1}{x} \), the domain excludes \( x = 0 \). This is because division by zero is undefined, leading to a restriction in the domain. Therefore, the domain of \( y = \frac{1}{x} \) includes all real numbers except \( x = 0 \).
For the function \( y = \frac{1}{x} \), the domain excludes \( x = 0 \). This is because division by zero is undefined, leading to a restriction in the domain. Therefore, the domain of \( y = \frac{1}{x} \) includes all real numbers except \( x = 0 \).
- To find the domain of a rational function, find where the denominator is zero and exclude those values.
- Domain restrictions ensure the function operates within a defined set of inputs.
Function Definition
A function in mathematics describes a relationship between two sets, where each input from the first set (domain) corresponds to exactly one output in the second set (range). Determining whether a given relation is a function involves checking if every input has a single, unique output.
With the function \( y = \frac{1}{x} \), each non-zero value of \( x \) produces a unique corresponding output for \( y \). This uniqueness satisfies the definition of a function.
With the function \( y = \frac{1}{x} \), each non-zero value of \( x \) produces a unique corresponding output for \( y \). This uniqueness satisfies the definition of a function.
- A key feature of a function is that no input \( x \) can have more than one corresponding \( y \).
- Graphs of functions often pass the "vertical line test," meaning no vertical line intersects the graph at more than one point.
Other exercises in this chapter
Problem 32
Solve each system by elimination. See Example 5 . $$ \left\\{\begin{array}{l} 5 x+3 y=-7 \\ 3(x-y)-7=0 \end{array}\right. $$
View solution Problem 32
Solve each system using substitution. $$ \left\\{\begin{array}{l} r-s+6 t=12 \\ r+6 s=-28 \\ 7 s+t=-26 \end{array}\right. $$
View solution Problem 33
Publishing. \(\quad\) A printer has two presses. The older press has a setup cost of \(\$ 210\) and can print the pages of a certain book for S5.98. The newer p
View solution Problem 33
Evaluate each determinant. $$ \left|\begin{array}{rrr} 1 & -4 & 1 \\ 3 & 0 & -2 \\ 3 & 1 & -2 \end{array}\right| $$
View solution