Problem 33
Question
Determine the common ratio, the fifth term, and the \(n\) th term of the geometric sequence. $$144,-12,1,-\frac{1}{12}, \dots$$
Step-by-Step Solution
Verified Answer
The common ratio is \(-\frac{1}{12}\), the fifth term is \(\frac{1}{144}\), and the \(n\) th term is \(144 \cdot \left(-\frac{1}{12}\right)^{n-1}\)."
1Step 1: Identify Two Consecutive Terms
Begin by identifying any two consecutive terms in the sequence. For this sequence, let's pick the first term 144 and the second term -12.
2Step 2: Calculate the Common Ratio
The common ratio \( r \) of a geometric sequence can be calculated by dividing the second term by the first term.\[r = \frac{-12}{144} = -\frac{1}{12}\]
3Step 3: Determine the Fifth Term
To find the fifth term of the sequence, use the formula for the \( n \) th term of a geometric sequence: \( a_n = a_1 \cdot r^{n-1} \). Here, \( a_1 = 144 \), \( r = -\frac{1}{12} \), and \( n = 5 \).\[a_5 = 144 \cdot \left(-\frac{1}{12}\right)^{4} = 144 \cdot \frac{1}{20736} = \frac{1}{144}\]
4Step 4: General Formula for the n-th Term
The formula for the \( n \) th term is \( a_n = a_1 \cdot r^{n-1} \). By plugging in the known values of \( a_1 \) and \( r \), we get\[a_n = 144 \cdot \left(-\frac{1}{12}\right)^{n-1}\]
Key Concepts
Common Ration-th Term FormulaFifth Term of a Sequence
Common Ratio
In geometric sequences, the common ratio is a crucial concept. It helps us understand how the sequence behaves from one term to the next. The common ratio, usually denoted as \( r \), is found by dividing one term in the sequence by the previous term. When you look at the sequence \(144, -12, 1, -\frac{1}{12}, \dots\), you'll notice each term is obtained by multiplying the previous term by the common ratio.
For example, to find the common ratio of our sequence, take \(-12\) (the second term) and divide it by \(144\) (the first term):
For example, to find the common ratio of our sequence, take \(-12\) (the second term) and divide it by \(144\) (the first term):
- \( r = \frac{-12}{144} = -\frac{1}{12} \)
n-th Term Formula
The \( n \)-th term formula is an essential tool in analyzing geometric sequences. It lets you find any term in the sequence without listing all previous terms. This formula is expressed as:
In the given sequence, the first term \( a_1 = 144 \) and the common ratio \( r = -\frac{1}{12}\). To find the general term, substitute these values into the formula:
- \( a_n = a_1 \cdot r^{n-1} \)
In the given sequence, the first term \( a_1 = 144 \) and the common ratio \( r = -\frac{1}{12}\). To find the general term, substitute these values into the formula:
- \( a_n = 144 \cdot \left(-\frac{1}{12}\right)^{n-1} \)
Fifth Term of a Sequence
Once you have the n-th term formula, calculating specific terms becomes straightforward. For instance, if you want to find the fifth term of the geometric sequence, you substitute \( n = 5 \) into the formula:
- \( a_5 = 144 \cdot \left(-\frac{1}{12}\right)^{4} \)
- First, calculate \( \left(-\frac{1}{12}\right)^{4} \). This causes the negative sign to disappear because of the even exponent, resulting in a positive fraction:
- \( \left(-\frac{1}{12}\right)^{4} = \frac{1}{20736} \).
- Multiply this by the first term (144): \( a_5 = 144 \cdot \frac{1}{20736} \).
Other exercises in this chapter
Problem 32
Find the \(n\)th term of a sequence whose first several terms are given. \(7,4,1,-2, \dots\)
View solution Problem 33
Determine the common difference, the fifth term, the \(n\) th term, and the 100 th term of the arithmetic sequence. $$4,10,16,22, \dots$$
View solution Problem 33
Find the indicated terms in the expansion of the given binomial. The middle term in the expansion of \(\left(x^{2}+1\right)^{18}\).
View solution Problem 33
Find the \(n\)th term of a sequence whose first several terms are given. \(5,-25,125,-625, \dots\)
View solution