Problem 33
Question
Chlorination of toluene in presence of light and heat followed by treatment with aqueous NaOH gives (a) o-cresol (b) p-cresol (c) 2,4 -dihydroxytoluene (d) benzoic acid
Step-by-Step Solution
Verified Answer
The product is (b) p-cresol.
1Step 1: Identify the reaction conditions
The problem involves two main reactions: chlorination in the presence of light and heat, followed by treatment with aqueous NaOH. The first step, chlorination, is a free radical substitution reaction that is accelerated by light.
2Step 2: Understand the effect of chlorination
In the presence of light, toluene undergoes chlorination primarily at the methyl position due to the formation of a stable benzylic radical. Therefore, the product after chlorination will be benzyl chloride.
3Step 3: Analyze the reaction with aqueous NaOH
Benzyl chloride can react with aqueous NaOH through a nucleophilic substitution reaction. The chlorine atom in benzyl chloride is replaced by an OH group, converting it into benzyl alcohol, which is the same as o/p-cresol after hydroxylation at the benzylic position.
4Step 4: Determine the possible products
Under the conditions given, the major products are ortho and para cresol due to the formation of benzyl chloride followed by hydrolysis. However, the position of substitution is typically indicated upon conditions favoring para substitution.
Key Concepts
ChlorinationFree Radical SubstitutionNucleophilic SubstitutionToluene Reactions
Chlorination
Chlorination is a vital organic reaction that involves the addition of chlorine atoms to an organic molecule. In the context of this exercise, chlorination primarily refers to the addition of chlorine to the methyl group of toluene. This process is initiated by exposing the reactants to light and heat, which helps generate chlorine radicals. These radicals are highly reactive and attack the hydrogen atoms on the methyl group of toluene.
- Chlorine radicals are formed in the presence of light and heat.
- Toluene, due to its methyl group, becomes susceptible to radical attack.
- The end product after this reaction is the chlorinated compound benzyl chloride.
Free Radical Substitution
Free radical substitution is a type of chemical reaction where a free radical replaces an atom in a molecule. It's a chain reaction that occurs in three steps: initiation, propagation, and termination.
- Initiation: In this step, chlorine molecules (Cl_2) dissociate into radicals under the influence of light.
- Propagation: These radicals react with toluene, abstracting hydrogen from the methyl group, forming a benzylic radical.
- Termination: The radicals combine to form stable molecules, ending the chain reaction.
Nucleophilic Substitution
Nucleophilic substitution is a crucial mechanism in organic chemistry. It involves the replacement of a leaving group (like a chlorine atom) by a nucleophile (such as the hydroxide ion). In this case, the reaction of benzyl chloride with aqueous NaOH exemplifies this process.
- The chlorine atom in benzyl chloride acts as a leaving group.
- The hydroxide ion from NaOH attacks the carbon atom bonded to the chlorine, forming an intermediate complex.
- This results in the formation of a new product, benzyl alcohol (or o/p-cresol).
Toluene Reactions
Toluene is an aromatic hydrocarbon that can undergo various reactions due to its stable benzene ring and reactive methyl group. In this context, the reaction sequence of chlorination followed by hydrolysis is central to understanding toluene's behavior.
- The methyl group on toluene can be chlorinated to give benzyl chloride.
- Subsequent treatment with aqueous NaOH leads to the formation of o/p-cresol.
- This demonstrates the interplay between radical and nucleophilic substitution mechanisms starting from toluene.
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